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Gravel Pit 1 year, 1 month ago.
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The question of all problems is rooted in its framework. However no framework in itself is complete if it must be composed of and composes further frameworks.
Hence all frameworks have an element of contradiction in these respects considering they are always incomplete and not self-referential with the progression of one framework necessitating the elimination of another (we see this in the evolution of computer languages and to some degree in logic).
The question of the framework it literally dependent upon the foundations which form it as the foundations, as often “assumed” universal axioms, in turn are frameworks in themselves.
Under these terms the question of universality is put to question as the foundations become the framework and the framework becomes the foundations.
Under these terms the self referential, while simultaneously progressive, limits of geometry as “directed movement” provide this necessary dualism while maintaining a neutral third nature of existing as “is” considering the simple point, line and circle cannot be “doubted” within any course of reason without simultaneously applying these limits in one form or another through the form of math, logic or basic spatial reasoning (which is embodied in directed movement).
Even standard language whether based in pure reason, empirical roots, or sophristy is still defined and determined as true or false according to these limits.

Anonymous1All problems should be viewed in comparison to the Absolute Cosmic reference point.
Paradoxes are works of fiction conjured up by the imagination. They should be studied as psychological phenomena, nothing more.
Firmly rooted footing for secure foundation and framework.
All problems should be viewed in comparison to the Absolute Cosmic reference point.
Paradoxes are works of fiction conjured up by the imagination. They should be studied as psychological phenomena, nothing more.Your first sentence says it all (if it implies what I believe you think it implies), point space is not only absolute but the origin of everything.
I will post some small work on a theoretical 1 dimensional point as the foundation for everything, as well as the nature of 0d points space as the foundation of relativism.
Paradoxes are the result of base division, where we take a phenomenon and seperate it. Paradoxes not only require a dualism but are inherently solvable by synthesis, hence they have a triadic quality.
The nature of psychology cannot be seperate from physics, or religion, math…or anything of a practical nature as well. This is considering the premise everything originates and exists through 1 point.
Firmly rooted footing for secure foundation and framework.
Recursion (Google or just think of Russian dolls) or a mirror effect (replication) is the foundation for framework, with both existing as inseparable components.
Directed movement is foundation for all phenomenon.
Satellite Data Codes
Satellite Data Codes are used by telemetry stations, forecast centers and others to encode solar geophysical data obtained from satellite-based sensors.
USXRA Codes
Solar x-ray events..Example:
Definition of symbols:
USXRA comes from Solar X-RAy events
I I I I I = station indicator
Y = last digit of year
MM = month of year, 01 = January, 02 = February, etc
. DD = UT day of monthSS = satellite
06 = GOES-6
07 = GOES-7
08 = GOES-8
09 = GOES-9
E = energy range
1 = .1-.8 nm
NN = number of events0 = indicates that the begin time of the event follows
HHmm = UT hour and minute of beginning of event0 = indicates that the maximum time of the event follows
HHmm = UT hour and minute of maximum for event0 = indicates that the the end time of the event follows
HHmm = UT hour and minute of end time of eventMaximum Flux:
Q = qualifier
0 = uncertain data
1 = certain data
ab = x-ray flux in Wm-1 where ab = a.b
S = sign of the exponent to apply to a.b
0 = positive
1 = negative
p = power of ten to apply to a.b
Note: abSp reported as 4192 would equal 4.1 x 10-1Wm-1Note: / is to be used for data not available.
Integrated flux (start thru end):
9 = qualifier
ab x-ray integrated flux in Jm-1 where ab = a.b
S = sign of the exponent to apply to a.b
0 = positive
1 = negative
p = power of ten to apply to a.b
Note: abSp reported as 5692 would equal 5.6 x 10-1Wm-1Note: / is to be used for data not available.
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.3 Conditionals and Loops
In the programs that we have examined to this point, each of the statements is executed once, in the order given. Most programs are more complicated because the sequence of statements and the number of times each is executed can vary. We use the term control flow to refer to statement sequencing in a program.
If statements. Most computations require different actions for different inputs.
The following code fragment uses an if statement to put the smaller of two int values in x and the larger of the two values in y, by exchanging the values in the two variables if necessary.
anatomy of an if statement
Flip.java uses Math.random() and an if-else statement to print the results of a coin flip.
The table below summarizes some typical situations where you might need to use an if or if-else statement.
examples of conditionalsWhile loops. Many computations are inherently repetitive. The while loop enables us to execute a group of statements many times. This enables us to express lengthy computations without writing lots of code.
The following code fragment computes the largest power of 2 that is less than or equal to a given positive integer n.
anatomy of a while loop
TenHellos.java prints “Hello World” 10 times.
PowersOfTwo.java takes an integer command-line argument n and prints all of the powers of 2 less than or equal to n.
For loops. The for loop is an alternate Java construct that allows us even more flexibility when writing loops.
For notation. Many loops follow the same basic scheme: initialize an index variable to some value and then use a while loop to test an exit condition involving the index variable, using the last statement in the while loop to modify the index variable. Java’s for loop is a direct way to express such loops.
anatomy of a for loop
Compound assignment idioms. The idiom i++ is a shorthand notation for i = i + 1.
Scope. The scope of a variable is the part of the program that can refer to that variable by name. Generally the scope of a variable comprises the statements that follow the declaration in the same block as the declaration. For this purpose, the code in the for loop header is considered to be in the same block as the for loop body.
Nesting. The if, while, and for statements have the same status as assignment statements or any other statements in Java; that is, we can use them wherever a statement is called for. In particular, we can use one or more of them in the body of another statement to make compound statements. To emphasize the nesting, we use indentation in the program code.
DivisorPattern.java has a for loop whose body contains a for loop (whose body is an if-else statement) and a print statement. It prints a pattern of asterisks where the ith row has an asterisk in each position corresponding to divisors of i (the same holds true for the columns).
MarginalTaxRate.java computes the marginal tax rate for a given income. It uses several nested if-else statements to test from among a number of mutually exclusive possibilities.
Loop examples.
examples of loops
Applications. The ability to program with loops and conditionals immediately opens up the world of computation to us.
Ruler subdivisions. RulerN.java takes an integer command-line argument n and prints the string of ruler subdivision lengths. This program illustrates one of the essential characteristics of loops—the program could hardly be simpler, but it can produce a huge amount of output.
Harmonic numbers
Finite sums. The computational paradigm used in PowersOfTwo.java is one that you will use frequently. It uses two variables—one as an index that controls a loop, and the other to accumulate a computational result. Program HarmonicNumber.java uses the same paradigm to evaluate the sum
Hn=11+12+13+14+…+1n
These numbers, which are known as the harmonic numbers, arise frequently in the analysis of algorithms.
Newton’s method. Newton’s methodSqrt.java uses a classic iterative technique known as Newton’s method to compute the square root of a positive number x: Start with an estimate t. If t is equal to x/t (up to machine precision), then t is equal to a square root of x, so the computation is complete. If not, refine the estimate by replacing t with the average of t and x/t. Each time we perform this update, we get closer to the desired answer.
Number conversion. Binary.java prints the binary (base 2) representation of the decimal number typed as the command-line argument. It is based on decomposing the number into a sum of powers of 2. For example, the binary representation of 106 is 11010102, which is the same as saying that 106 = 64 + 32 + 8 + 2. To compute the binary representation of n, we consider the powers of 2 less than or equal to n in decreasing order to determine which belong in the binary decomposition (and therefore correspond to a 1 bit in the binary representation).
Gambler’s ruin. gambler’s ruin Suppose a gambler makes a series of fair $1 bets, starting with $50, and continue to play until she either goes broke or has $250. What are the chances that she will go home with $250, and how many bets might she expect to make before winning or losing? Gambler.java is a simulation that can help answer these questions. It takes three command-line arguments, the initial stake ($50), the goal amount ($250), and the number of times we want to simulate the game.
Prime factorization. Factors.java takes an integer command-line argument n and prints its prime factorization. In contrast to many of the other programs that we have seen (which we could do in a few minutes with a calculator or pencil and paper), this computation would not be feasible without a computer.
Other conditional and loop constructs. To be complete, we consider four more Java constructs related to conditionals and loops. They are used much less frequently than the if, while, and for statements that we’ve been working with, but it is worthwhile to be aware of them.
Break statements. In some situations, we want to immediate exit a loop without letting it run to completion. Java provides the break statement for this purpose. Prime.java takes an integer command-line argument n and prints true if n is prime, and false otherwise. There are two different ways to leave this loop: either the break statement is executed (because n is not prime) or the loop-continuation condition is not satisfied (because n is prime).
Note that the break statement does not apply to if or if-else statements. In a famous programming bug, the U.S. telephone network crashed because a programmer intended to use a break statement to exit a complicated if statement.Continue statements. Java also provides a way to skip to the next iteration of a loop: the continue statement. When a continue is executed within the body of a for loopy, the flow of control transfers directly to the increment statement for the next iteration of the loop.
Switch statements. The if and if-else statements allow one or two alternatives. Sometimes, a computation naturally suggests more than two mutually exclusive alternatives. Java provides the switch statement for this purpose. NameOfDay.java takes an integer between 0 and 6 as a command-line argument and uses a switch statement to print the corresponding name of the day (Sunday to Saturday).
Do–while loops. A do-while loop is almost the same as a while loop except that the loop-continuation condition is omitted the first time through the loop. RandomPointInCircle.java sets x and y so that (x, y) is randomly distributed inside the circle centered at (0, 0) with radius 1.
do-while loop
With Math.random() we get points that are randomly distributed in the 2-by-2 square center at (0, 0). We just generate points in this region until we find one that lies inside the unit disk. We always want to generate at least one point so a do-while loop is most appropriate. We must declare x and y outside the loop since we will want to access their values after the loop terminates.We don’t use the following two flow control statements in this textbook, but include them here for completeness.
Conditional operator. The conditional operator ?: is a ternary operator (three operands) that enables you to embed a conditional within an expression. The three operands are separated by the ? and : symbols. If the first operand (a boolean expression) is true, the result has the value of the second expression; otherwise it has the value of the third expression.
int min = (x < y) ? x : y;
Labeled break and continue statements. The break and continue statements apply to the innermost for or while loop. Sometimes we want to jump out of several levels of nested loops. Java provides the labeled break and labeled continue statements to accomplish this. Here is an example.
Exercises
Write a program AllEqual.java that takes three integer command-line arguments and prints equal if all three are equal, and not equal otherwise.
Write a program RollLoadedDie.java that prints the result of rolling a loaded die such that the probability of getting a 1, 2, 3, 4, or 5 is 1/8 and the probability of getting a 6 is 3/8.
Rewrite TenHellos.java to make a program Hellos.java that takes the number of lines to print as a command-line argument. You may assume that the argument is less than 1000. Hint: consider using i % 10 and i % 100 to determine whether to use “st”, “nd”, “rd”, or “th” for printing the ith Hello.
Write a program FivePerLine.java that, using one for loop and one if statement, prints the integers from 1000 to 2000 with five integers per line. Hint: use the % operator.
Write a program FunctionGrowth.java that prints a table of the values of ln n, n, n ln n, n2, n3, and 2n for n = 16, 32, 64, …, 2048. Use tabs (‘\t’ characters) to line up columns.
What is the value of m and n after executing the following code?
int n = 123456789;
int m = 0;
while (n != 0) {
m = (10 * m) + (n % 10);
n = n / 10;
}
What does the following code print out?
int f = 0, g = 1;
for (int i = 0; i <= 15; i++) {
System.out.println(f);
f = f + g;
g = f – g;
}
Unlike the harmonic numbers, the sum 1/1 + 1/4 + 1/9 + 1/16 + … + 1/n2 does converge to a constant as n grows to infinity. (Indeed, the constant is π2 / 6, so this formula can be used to estimate the value of π.) Which of the following for loops computes this sum? Assume that n is an int initialized to 1000000 and sum is a double initialized to 0.
(a) for (int i = 1; i <= n; i++)
sum = sum + 1 / (i * i);(b) for (int i = 1; i <= n; i++)
sum = sum + 1.0 / i * i;(c) for (int i = 1; i <= n; i++)
sum = sum + 1.0 / (i * i);(d) for (int i = 1; i <= n; i++)
sum = sum + 1 / (1.0 * i * i);
Modify Binary.java to get a program Modify Kary.java that takes a second command-line argument K and converts the first argument to base K. Assume the base is between 2 and 16. For bases greater than 10, use the letters A through F to represent the 11th through 16th digits, respectively.
Write a program code fragment that puts the binary representation of a positive integer n into a String variable s.
Creative Exercises
Ramanujan’s taxi. S. Ramanujan was an Indian mathematician who became famous for his intuition for numbers. When the English mathematician G. H. Hardy came to visit him in the hospital one day, Hardy remarked that the number of his taxi was 1729, a rather dull number. To which Ramanujan replied, “No, Hardy! No, Hardy! It is a very interesting number. It is the smallest number expressible as the sum of two cubes in two different ways.” Verify this claim by writing a program Ramanujan.java that takes an integer command-line argument n and prints all integers less than or equal to n that can be expressed as the sum of two cubes in two different ways – find distinct positive integers a, b, c, and d such that a3 + b3 = c3 + d3. Use four nested for loops.
Now, the license plate 87539319 seems like a rather dull number. Determine why it’s not.Checksums. The International Standard Book Number (ISBN) is a 10 digit code that uniquely specifies a book. The rightmost digit is a checksum digit which can be uniquely determined from the other 9 digits from the condition that d1 + 2d2 + 3d3 + … + 10d10 must be a multiple of 11 (here di denotes the ith digit from the right). The checksum digit d1 can be any value from 0 to 10: the ISBN convention is to use the value X to denote 10. Example: the checksum digit corresponding to 020131452 is 5 since is the only value of d1 between 0 and and 10 for which d1 + 2*2 + 3*5 + 4*4 + 5*1 + 6*3 + 7*1 + 8*0 + 9*2 + 10*0 is a multiple of 11. Write a program ISBN.java that takes a 9-digit integer as a command-line argument, computes the checksum, and prints the 10-digit ISBN number. It’s ok if you don’t print any leading 0s.
Exponential function. Assume that x is a positive variable of type double. Write a program Exp.java that computes e^x using the Taylor series expansion
ex=1+x+x22!+x33+x44!+…
Trigonometric functions. Write two programs Sin.java and Cos.java that compute sin x and cos x using the Taylor series expansions
sinx=x−x33!+x55!−x77!+…
cosx=1−x22!+x44!−x66!+…
Game simulation. In the game show Let’s Make a Deal, a contestant is presented with three doors. Behind one door is a valuable prize, behind the other two are gag gifts. After the contestant chooses a door, the host opens up one of the other two doors (never revealing the prize, of course). The contestant is then given the opportunity to switch to the other unopened door. Should the contestant do so? Intuitively, it might seem that the contestant’s initial choice door and the other unopened door are equally likely to contain the prize, so there would be no incentive to switch. Write a program MonteHall.java to test this intuition by simulation. Your program should take an integer command-line argument n, play the game n times using each of the two strategies (switch or don’t switch) and print the chance of success for each strategy. Or you can play the game here.
Euler’s sum-of-powers conjecture. In 1769 Leonhard Euler formulated a generalized version of Fermat’s Last Theorem, conjecturing that at least n nth powers are needed to obtain a sum that is itself an nth power, for n > 2. Write a program Euler.java to disprove Euler’s conjecture (which stood until 1967), using a quintuply nested loop to find four positive integers whose 5th power sums to the 5th power of another positive integer. That is, find a, b, c, d, and e such that a5 + b5 + c5 + d5 = e5. Use the long data type.
Web Exercises
Write a program RollDie.java that generates the result of rolling a fair six-sided die (an integer between 1 and 6).
Write a program that takes three integer command-line arguments a, b, and c and print the number of distinct values (1, 2, or 3) among a, b, and c.
Write a program that takes five integer command-line arguments and prints the median (the third largest one).
(hard) Now, try to compute the median of 5 elements such that when executed, it never makes more than 6 total comparisons.
How can I create in an infinite loop with a for loop?
Solution: for(;;) is the same as while(true).What’s wrong with the following loop?
boolean done = false;
while (done = false) {
…
}
The while loop condition uses = instead of == so it is an assignment statement (which makes done always false and the body of the loop will never be executed). It’s better to style to avoid using ==.
boolean done = false;
while (!done) {
…
}
What’s wrong with the following loop that is intended to compute the sum of the integers 1 through 100?
for (int i = 1; i <= N; i++) {
int sum = 0;
sum = sum + i;
}
System.out.println(sum);
The variable sum should be defined outside the loop. By defining it inside the loop, a new variable sum is initialized to 0 each time through the loop; also it is not even accessible outside the loop.
Write a program Hurricane.java that that takes the wind speed (in miles per hour) as an integer command-line argument and prints whether it qualifies as a hurricane, and if so, whether it is a Category 1, 2, 3, 4, or 5 hurricane. Below is a table of the wind speeds according to the Saffir-Simpson scale.
CategoryWind Speed (mph)
174 – 95
296 – 110
3111 – 130
4131 – 155
5155 and above
What is wrong with the following code fragment?
double x = -32.2;
boolean isPositive = (x > 0);
if (isPositive = true) System.out.println(x + ” is positive”);
else System.out.println(x + ” is not positive”);
Solution: It uses the assignment operator = instead of the equality operator ==. A better solution is to write if (isPositive).Change/add one character so that the following program prints 20 xs. There are two different solutions.
int i = 0, n = 20;
for (i = 0; i < n; i–)
System.out.print(“x”);
Solution: Replace the i < n condition with -i < n. Replace the i– with n–. ( In C, there is a third: replace the < with a +.)
What does the following code fragment do?
if (x > 0);
System.out.println(“positive”);
Solution: always prints positive regardless of the value of x because of the extra semicolon after the if statement.RGB to HSB converter. Write a program RGBtoHSV.java that takes an RGB color (three integers between 0 and 255) and transforms it to an HSB color (three different integers between 0 and 255). Write a program HSVtoRGB.java that applies the inverse transformation.
Boys and girls. A couple beginning a family decides to keep having children until they have at least one of either sex. Estimate the average number of children they will have via simulation. Also estimate the most common outcome (record the frequency counts for 2, 3, and 4 children, and also for 5 and above). Assume that the probability p of having a boy or girl is 1/2.
What does the following program do?
public static void main(String[] args) {
int N = Integer.parseInt(args[0]);
int x = 1;
while (N >= 1) {
System.out.println(x);
x = 2 * x;
N = N / 2;
}
}
Solution: Prints all of the powers of 2 less than or equal to n.
Boys and girls. Repeat the previous question, but assume the couple keeps having children until they have another child which is of the same sex as the first child. How does your answer change if p is different from 1/2?
Surprisingly, the average number of children is 2 if p = 0 or 1, and 3 for all other values of p. But the most likely value is 2 for all values of p.Given two positive integers a and b, what result does the following code fragment leave in c
c = 0;
while (b > 0) {
if (b % 2 == 1) c = c + a;
b = b / 2;
a = a + a;
}
Solution: a * b.Write a program using a loop and four conditionals to print
12 midnight
1am
2am
…
12 noon
1pm
…
11pm
What does the following program print?
public class Test {
public static void main(String[] args) {
if (10 > 5);
else; {
System.out.println(“Here”);
};
}
}
Alice tosses a fair coin until she sees two consecutive heads. Bob tosses another fair coin until he sees a head followed by a tail. Write a program to estimate the probability that Alice will make fewer tosses than Bob? Solution: 39/121.
Rewrite DayOfWeek.java from Exercise 1.2.29 so that it prints the day of the week as Sunday, Monday, and so forth instead of an integer between 0 and 6. Use a switch statement.
Number-to-English. Write a program to read in a command line integer between -999,999,999 and 999,999,999 and print the English equivalent. Here is an exhaustive list of words that your program should use: negative, zero, one, two, three, four, five, six, seven, eight, nine, ten, eleven, twelve, thirteen, fourteen, fifteen, sixteen, seventeen, eighteen, nineteen, twenty, thirty, forty, fifty, sixty, seventy, eighty, ninety, hundred, thousand, million . Don’t use hundred, when you can use thousand, e.g., use one thousand five hundred instead of fifteen hundred. Reference.
Gymnastics judging. A gymnast’s score is determined by a panel of 6 judges who each decide a score between 0.0 and 10.0. The final score is determined by discarding the high and low scores, and averaging the remaining 4. Write a program GymnasticsScorer.java that takes 6 real command line inputs representing the 6 scores and prints their average, after throwing out the high and low scores.
Quarterback rating. To compare NFL quarterbacks, the NFL devised a the quarterback rating formula based on the quarterbacks number of completed passes (A), pass attempts (B), passing yards (C), touchdown passes (D), and interception (E) as follows:
Completion ratio: W = 250/3 * ((A / B) – 0.3).
Yards per pass: X = 25/6 * ((C / B) – 3).
Touchdown ratio: Y = 1000/3 * (D / B)
Interception ratio: Z = 1250/3 * (0.095 – (E / B))
The quarterback rating is computed by summing up the above four quantities, but rounding up or down each value so that it is at least 0 and and at most 475/12. Write a program QuarterbackRating.java that takes five command line inputs A, B, C, D, and E, and prints the quarterback rating. Use your program to compute Steve Young’s 1994 record-setting season (112.8) in which he completed 324 of 461 passes for 3,969 yards, and threw 35 touchdowns and 10 interceptions. As of 2014, the all-time single-season record is 122.5 by Aaron Rodgers in 2011.
Decimal expansion of rational numbers. Given two integers p and q, the decimal expansion of p/q has an infinitely repeating cycle. For example, 1/33 = 0.03030303…. We use the notation 0.(03) to denote that 03 repeats indefinitely. As another example, 8639/70000 = 0.1234(142857). Write a program DecimalExpansion.java that reads in two command line integers p and q and prints the decimal expansion of p/q using the above notation. Hint: use Floyd’s rule.
Friday the 13th. What is the maximum number of consecutive days in which no Friday the 13th occurs? Hint: The Gregorian calendar repeats itself every 400 years (146097 days) so you only need to worry about a 400 year interval.
Solution: 426 (e.g., from 8/13/1999 to 10/13/2000).January 1. Is January 1 more likely to fall on a Saturday or Sunday? Write a program to determine the number of times each occurs in a 400 year interval.
Solution: Sunday (58 times) is more likely than Saturday (56 times).What do the following two code fragments do?
for (int i = 0; i < N; i++)
for (int j = 0; j < N; j++)
if (i != j) System.out.println(i + “, ” + j);for (int i = 0; i < N; i++)
for (int j = 0; (i != j) && (j < N); j++)
System.out.println(i + “, ” + j);
Determine what value gets printed out without using a computer. Choose the correct answer from 0, 100, 101, 517, or 1000.
int cnt = 0;
for (int i = 0; i < 10; i++)
for (int j = 0; j < 10; j++)
for (int k = 0; k < 10; k++)
if (2*i + j >= 3*k)
cnt++;
System.out.println(cnt);
Rewrite CarLoan.java from Creative Exercise XYZ so that it properly handles an interest rate of 0% and avoids dividing by 0.
Write the shortest Java program you can that takes an integer command-line argument n and prints true if (1 + 2 + … + n) 2 is equal to (13 + 23 + … + n3).
Solution: Always print true.Modify Sqrt.java so that it reports an error if the user enters a negative number and works properly if the user enters zero.
What happens if we initialize t to -x instead of x in program Sqrt.java?
Sample standard deviation of uniform distribution. Modify Exercise 8 so that it prints the sample standard deviation in addition to the average.
Sample standard deviation of normal distribution. that takes an integer N as a command-line argument and uses Web Exercise 1 from Section 1.2 to print N standard normal random variables, and their average value, and sample standard deviation.
Loaded dice. [Stephen Rudich] Suppose you have three, three sided dice. A: {2, 6, 7}, B: { 1, 5, 9}, and C: {3, 4, 8}. Two players roll a die and the one with the highest value wins. Which die would you choose? Solution: A beats B with probability 5/9, B beats C with probability 5/9 and C beats A with probability 5/9. Be sure to choose second!
Thue–Morse sequence. Write a program ThueMorse.java that reads in a command line integer n and prints the Thue–Morse sequence of order n. The first few strings are 0, 01, 0110, 01101001. Each successive string is obtained by flipping all of the bits of the previous string and concatenating the result to the end of the previous string. The sequence has many amazing properties. For example, it is a binary sequence that is cube-free: it does not contain 000, 111, 010101, or sss where s is any string. It is self-similar: if you delete every other bit, you get another Thue–Morse sequence. It arises in diverse areas of mathematics as well as chess, graphic design, weaving patterns, and music composition.
Program Binary.java prints the binary representation of a decimal number n by casting out powers of 2. Write an alternate version Program Binary2.java that is based on the following method: Write 1 if n is odd, 0 if n is even. Divide n by 2, throwing away the remainder. Repeat until n = 0 and read the answer backwards. Use % to determine whether n is even, and use string concatenation to form the answer in reverse order.
What does the following code fragment do?
int digits = 0;
do {
digits++;
n = n / 10;
} while (n > 0);
Solution: The number of bits in the binary representation of a natural number n. We use a do-while loop so that code output 1 if n = 0.Write a program NPerLine.java that takes an integer command-line argument n and prints the integers from 10 to 99 with n integers per line.
Modify NPerLine.java so that it prints the integers from 1 to 1000 with n integers per line. Make the integers line up by printing the right number of spaces before an integer (e.g., three for 1-9, two for 10-99, and one for 100-999).
Suppose a, b, and c are random number uniformly distributed between 0 and 1. What is the probability that a, b, and c form the side length of some triangle? Hint: they will form a triangle if and only if the sum of every two values is larger than the third.
Repeat the previous question, but calculate the probability that the resulting triangle is obtuse, given that the three numbers for a triangle. Hint: the three lengths will form an obtuse triangle if and only if (i) the sum of every two values is larger than the third and (ii) the sum of the squares of every two side lengths is greater than or equal to the square of the third.
Answer.What is the value of s after executing the following code?
int M = 987654321;
String s = “”;
while (M != 0) {
int digit = M % 10;
s = s + digit;
M = M / 10;
}
What is the value of i after the following confusing code is executed?
int i = 10;
i = i++;
i = ++i;
i = i++ + ++i;
Moral: don’t write code like this.Formatted ISBN number. Write a program ISBN2.java that reads in a 9 digit integer from a command-line argument, computes the check digit, and prints the fully formatted ISBN number, e.g, 0-201-31452-5.
UPC codes. The Universal Product Code (UPC) is a 12 digit code that uniquely specifies a product. The least significant digit d1(rightmost one) is a check digit which is the uniquely determined by making the following expression a multiple of 10:
(d1 + d3 + d5 + d7 + d9 + d11) + 3 (d2 + d4 + d6 + d8 + d10 + d12)
As an example, the check digit corresponding to 0-48500-00102 (Tropicana Pure Premium Orange Juice) is 8 since(8 + 0 + 0 + 0 + 5 + 4) + 3 (2 + 1 + 0 + 0 + 8 + 0) = 50
and 50 is a multiple of 10. Write a program that reads in a 11 digit integer from a command line parameter, computes the check digit, and prints the the full UPC. Hint: use a variable of type long to store the 11 digit number.Write a program that reads in the wind speed (in knots) as a command line argument and prints its force according to the Beaufort scale. Use a switch statement.
Making change. Write a program that reads in a command line integer N (number of pennies) and prints the best way (fewest number of coins) to make change using US coins (quarters, dimes, nickels, and pennies only). For example, if N = 73 then print
2 quarters
2 dimes
3 pennies
Hint: use the greedy algorithm. That is, dispense as many quarters as possible, then dimes, then nickels, and finally pennies.Write a program Triangle.java that takes a command-line argument N and prints an N-by-N triangular pattern like the one below.
* * * * * *
. * * * * *
. . * * * *
. . . * * *
. . . . * *
. . . . . *
Write a program Ex.java that takes a command-line argument N and prints a (2N + 1)-by-(2N + 1) ex like the one below. Use two for loops and one if-else statement.
* . . . . . *
. * . . . * .
. . * . * . .
. . . * . . .
. . * . * . .
. * . . . * .
* . . . . . *
Write a program BowTie.java that takes a command-line argument N and prints a (2N + 1)-by-(2N + 1) bowtie like the one below. Use two for loops and one if-else statement.
* . . . . . *
* * . . . * *
* * * . * * *
* * * * * * *
* * * . * * *
* * . . . * *
* . . . . . *
Write a program Diamond.java that takes a command-line argument N and prints a (2N + 1)-by-(2N + 1) diamond like the one below.
% java Diamond 4
. . . . * . . . .
. . . * * * . . .
. . * * * * * . .
. * * * * * * * .
* * * * * * * * *
. * * * * * * * .
. . * * * * * . .
. . . * * * . . .
. . . . * . . . .
Write a program Heart.java that takes a command-line argument N and prints a heart.
What does the program Circle.java print out when N = 5?
for (int i = -N; i <= N; i++) {
for (int j = -N; j <= N; j++) {
if (i*i + j*j <= N*N) System.out.print(“* “);
else System.out.print(“. “);
}
System.out.println();
}
Seasons. Write a program Season.java that takes two command line integers M and D and prints the season corresponding to month M (1 = January, 12 = December) and day D in the northern hemisphere. Use the following table
SEASONFROMTO
SpringMarch 21June 20
SummerJune 21September 22
FallSeptember 23December 21
WinterDecember 21March 20Zodiac signs. Write a program Zodiac.java that takes two command line integers M and D and prints the Zodiac sign corresponding to month M (1 = January, 12 = December) and day D. Use the following table
SIGNFROMTO
CapricornDecember 22January 19
AquariusJanuary 20February 17
PiscesFebruary 18March 19
AriesMarch 20April 19
TaurusApril 20May 20
GeminiMay 21June 20
CancerJune 21July 22
LeoJuly 23August 22
VirgoAugust 23September 22
LibraSeptember 23October 22
ScorpioOctober 23November 21
SagittariusNovember 22December 21
Muay Thai kickboxing. Write a program that reads in the weight of a Muay Thai kickboxer (in pounds) as a command-line argument and prints their weight class. Use a switch statement.
CLASSFROMTO
Flyweight0112
Super flyweight112115
Bantamweight115118
Super bantamweight118122
Featherweight122126
Super featherweight126130
Lightweight130135
Super lightweight135140
Welterweight140147
Super welterweight147154
Middleweight154160
Super middleweight160167
Light heavyweight167175
Super light heavyweight175183
Cruiserweight183190
Heavyweight190220
Super heavyweight220–
Euler’s sum of powers conjecture. In 1769 Euler generalized Fermat’s Last Theorem and conjectured that it is impossible to find three 4th powers whose sum is a 4th power, or four 5th powers whose sum is a 5th power, etc. The conjecture was disproved in 1966 by exhaustive computer search. Disprove the conjecture by finding positive integers a, b, c, d, and e such that a5 + b5 + c5 + d5= e5. Write a program Euler.java that reads in a command line parameter N and exhaustively searches for all such solutions with a, b, c, d, and e less than or equal to N. No counterexamples are known for powers greater than 5, but you can join EulerNet, a distributed computing effort to find a counterexample for sixth powers.
Blackjack. Write a program Blackjack.java that takes three command line integers x, y, and z representing your two blackjack cards x and y, and the dealers face-up card z, and prints the “standard strategy” for a 6 card deck in Atlantic city. Assume that x, y, and z are integers between 1 and 10, representing an ace through a face card. Report whether the player should hit, stand, or split according to these strategy tables. (When you learn about arrays, you will encounter an alternate strategy that does not involve as many if-else statements).
Blackjack with doubling. Modify the previous exercise to allow doubling.
Projectile motion. The following equation gives the trajectory of a ballistic missile as a function of the initial angle theta and windspeed: xxxx. Write a java program to print the (x, y) position of the missile at each time step t. Use trial and error to determine at what angle you should aim the missile if you hope to incinerate a target located 100 miles due east of your current location and at the same elevation. Assume the windspeed is 20 mph due east.
World series. The baseball world series is a best of 7 competition, where the first team to win four games wins the World Series. Suppose the stronger team has probability p > 1/2 of winning each game. Write a program to estimate the chance that the weaker teams wins the World Series and to estimate how many games on average it will take.
Consider the equation (9/4)^x = x^(9/4). One solution is 9/4. Can you find another one using Newton’s method?
Sorting networks. Write a program Sort3.java with three if statements (and no loops) that reads in three integers a, b, and c from the command line and prints them out in ascending order.
if (a > b) swap a and b
if (a > c) swap a and c
if (b > c) swap b and c
Oblivious sorting network. Convince yourself that the following code fragment rearranges the integers stored in the variables A, B, C, and D so that A <= B <= C <= D.
if (A > B) { t = A; A = B; B = t; }
if (B > C) { t = B; B = C; C = t; }
if (A > B) { t = A; A = B; B = t; }
if (C > D) { t = C; C = D; D = t; }
if (B > C) { t = B; B = C; C = t; }
if (A > B) { t = A; A = B; B = t; }
if (D > E) { t = D; D = E; E = t; }
if (C > D) { t = C; C = D; D = t; }
if (B > C) { t = B; B = C; C = t; }
if (A > B) { t = A; A = B; B = t; }
Devise a sequence of statements that would sort 5 integers. How many if statements does your program use?
Optimal oblivious sorting networks. Create a program that sorts four integers using only 5 if statements, and one that sorts five integers using only 9 if statements of the type above? Oblivious sorting networks are useful for implementing sorting algorithms in hardware. How can you check that your program works for all inputs?
Solution: Sort4.java sorts 4 elements using 5 compare-exchanges. Sort5.java sorts 5 elements using 9 compare-exchanges.The 0-1 principle asserts that you can verify the correctness of a (deterministic) sorting algorithm by checking whether it correctly sorts an input that is a sequence of 0s and 1s. Thus, to check that Sort5.java works, you only need to test it on the 2^5 = 32 possible inputs of 0s and 1s.
Optimal oblivious sorting (challenging). Find an optimal sorting network for 6, 7, and 8 inputs, using 12, 16, and 19 if statements of the form in the previous problem, respectively.
Solution: Sort6.java is the solution for sorting 6 elements.Optimal non-oblivious sorting. Write a program that sorts 5 inputs using only 7 comparisons. Hint: First compare the first two numbers, the second two numbers, and the larger of the two groups, and label them so that a < b < d and c < d. Second, insert the remaining element e into its proper place in the chain a < b < d by first comparing against b, then either a or d depending on the outcome. Third, insert c into the proper place in the chain involving a, b, d, and e in the same manner that you inserted e (with the knowledge that c < d). This uses 3 (first step) + 2 (second step) + 2 (third step) = 7 comparisons. This method was first discovered by H. B. Demuth in 1956.
Weather balloon. (Etter and Ingber, p. 123) Suppose that h(t) = 0.12t4 + 12t3 – 380t2 + 4100t + 220 represents the height of a weather balloon at time t (measured in hours) for the first 48 hours after its launch. Create a table of the height at time t for t = 0 to 48. What is its maximum height? Solution: t = 5.
Will the following code fragment compile? If so, what will it do?
int a = 10, b = 18;
if (a = b) System.out.println(“equal”);
else System.out.println(“not equal”);
Solution: It uses the assignment operator = instead of the equality operator == in the conditional. In Java, the result of this statement is an integer, but the compiler expects a boolean. As a result, the program will not compile. In some languages (notably C and C++), this code fragment will set the variable a to 18 and print equal without an error.Gotcha 1. What does the following code fragment do?
boolean a = false;
if (a = true) System.out.println(“yes”);
else System.out.println(“no”);
Solution: it prints yes. Note that the conditional uses = instead of ==. This means that a is assigned the value true As a result, the conditional expression evaluates to true. Java is not immune to the = vs. == error described in the previous exercise. For this reason, it is much better style to use if (a) or if (!a) when testing booleans.
Gotcha 2. What does the following code fragment do?
int a = 17, x = 5, y = 12;
if (x > y);
{
a = 13;
x = 23;
}
System.out.println(a);
Solution: Always prints 13 since there is a spurious semicolon after the if statement. Thus, the assignment statement a = 13; will be executed even though (x <= y) It is legal (but uncommon) to have a block that does not belong to a conditional statement, loop, or method.
Gotcha 3. What does the following code fragment do?
for (int x = 0; x < 100; x += 0.5) {
System.out.println(x);
}
Solution: It goes into an infinite loop printing 0. The compound assignment statement x += 0.5 is equivalent to x = (int) (x + 0.5).
What does the following code fragment do?
int income = Integer.parseInt(args[0]);
if (income >= 311950) rate = .35;
if (income >= 174700) rate = .33;
if (income >= 114650) rate = .28;
if (income >= 47450) rate = .25;
if (income >= 0) rate = .22;
System.out.println(rate);
It does not compile because the compile cannot guarantee that rate is initialized. Use if-else instead.
Application of Newton’s method. Write a program BohrRadius.java that finds the radii where the probability of finding the electron in the 4s excited state of hydrogen is zero. The probability is given by: (1 – 3r/4 + r2/8 – r3/192)2 e-r/2, where r is the radius in units of the Bohr radius (0.529173E-8 cm). Use Newton’s method. By starting Newton’s method at different values of r, you can discover all three roots. Hint: use initial values of r= 0, 5, and 13. Challenge: explain what happens if you use an initial value of r = 4 or 12.
Pepys problem. In 1693, Samuel Pepys asked Isaac Newton which was more likely: getting at least one 1 when rolling a fair die 6 times or getting at least two 1’s when rolling a fair die 12 times. Write a program Pepys.java that uses simulation to determine the correct answer.
What is the value of the variable s after running the following loop when N = 1, 2, 3, 4, and 5.
String s = “”;
for (int i = 1; i <= N; i++) {
if (i % 2 == 0) s = s + i + s;
else s = i + s + i;
}
Solution: Palindrome.java.Body mass index. The body mass index (BMI) is the ratio of the weight of a person (in kilograms) to the square of the height (in meters). Write a program BMI.java that takes two command-line arguments, weight and height, computes the BMI, and prints the corresponding BMI category:
Starvation: less than 15
Anorexic: less than 17.5
Underweight: less than 18.5
Ideal: greater than or equal to 18.5 but less than 25
Overweight: greater than or equal to 25 but less than 30
Obese: greater than or equal to 30 but less than 40
Morbidly Obese: greater than or equal to 40
Reynolds number. The Reynolds number is the ratio if inertial forces to viscous forces and is an important quantity in fluid dynamics. Write a program that takes in 4 command-line arguments, the diameter d, the velocity v, the density rho, and the viscosity mu, and prints the Reynold’s number d * v * rho / mu (assuming all arguments are in SI units). If the Reynold’s number is less than 2000, print laminar flow, if it’s between 2000 and 4000, print transient flow, and if it’s more than 4000, print turbulent flow.
Wind chill revisited. The wind chill formula from Exercise 1.2.14 is only valid if the wind speed is above 3MPH and below 110MPH and the temperature is below 50 degrees Fahrenheit and above -50 degrees. Modify your solution to print an error message if the user types in a value outside the allowable range.
Point on a sphere. Write a program to print the (x, y, z) coordinates of a random point on the surface of a sphere. Use Marsaglia’ method: pick a random point (a, b) in the unit circle as in the do-while example. Then, set x = 2a sqrt(1 – a^2 – b^2), y = 2b sqrt(1 – a^2 – b^2), z = 1 – 2(a^2 + b^2).
Powers of k. Write a program PowersOfK.java that takes an integer K as command-line argument and prints all the positive powers of K in the Java long data type. Note: the constant Long.MAX_VALUE is the value of the largest integer in long.
Square root, revisited. Why not use the loop-continuation condition (Math.abs(t*t – c) > EPSILON) in Sqrt.java instead of Math.abs(t – c/t) > t*EPSILON)?
Solution: Surprisingly, it can lead to inaccurate results or worse. For example, if you supply SqrtBug.java with the command-line argument 1e-50, you get 1e-50 as the answer (instead of 1e-25); if you supply 16664444, you get an infinite loop!What happens when you try to compile the following code fragment?
double x;
if (a >= 0) x = 3.14;
if (a < 0) x = 2.71;
System.out.println(x);
Solution: It complains that the variable x might not have been initialized (even though we can clearly see that x will be initialized by one of the two if statements). You can avoid this problem here by using if-else.Last modified on October 02, 2017.
Copyright © 2000–2018 Robert Sedgewick and Kevin Wayne. All rights reserved.

.3 Conditionals and Loops
In the programs that we have examined to this point, each of the statements is executed once, in the order given. Most programs are more complicated because the sequence of statements and the number of times each is executed can vary. We use the term control flow to refer to statement sequencing in a program.
If statements. Most computations require different actions for different inputs.
The following code fragment uses an if statement to put the smaller of two int values in x and the larger of the two values in y, by exchanging the values in the two variables if necessary.
anatomy of an if statement
Flip.java uses Math.random() and an if-else statement to print the results of a coin flip.
The table below summarizes some typical situations where you might need to use an if or if-else statement.
examples of conditionalsWhile loops. Many computations are inherently repetitive. The while loop enables us to execute a group of statements many times. This enables us to express lengthy computations without writing lots of code.
The following code fragment computes the largest power of 2 that is less than or equal to a given positive integer n.
anatomy of a while loop
TenHellos.java prints “Hello World” 10 times.
PowersOfTwo.java takes an integer command-line argument n and prints all of the powers of 2 less than or equal to n.
For loops. The for loop is an alternate Java construct that allows us even more flexibility when writing loops.
For notation. Many loops follow the same basic scheme: initialize an index variable to some value and then use a while loop to test an exit condition involving the index variable, using the last statement in the while loop to modify the index variable. Java’s for loop is a direct way to express such loops.
anatomy of a for loop
Compound assignment idioms. The idiom i++ is a shorthand notation for i = i + 1.
Scope. The scope of a variable is the part of the program that can refer to that variable by name. Generally the scope of a variable comprises the statements that follow the declaration in the same block as the declaration. For this purpose, the code in the for loop header is considered to be in the same block as the for loop body.
Nesting. The if, while, and for statements have the same status as assignment statements or any other statements in Java; that is, we can use them wherever a statement is called for. In particular, we can use one or more of them in the body of another statement to make compound statements. To emphasize the nesting, we use indentation in the program code.
DivisorPattern.java has a for loop whose body contains a for loop (whose body is an if-else statement) and a print statement. It prints a pattern of asterisks where the ith row has an asterisk in each position corresponding to divisors of i (the same holds true for the columns).
MarginalTaxRate.java computes the marginal tax rate for a given income. It uses several nested if-else statements to test from among a number of mutually exclusive possibilities.
Loop examples.
examples of loops
Applications. The ability to program with loops and conditionals immediately opens up the world of computation to us.
Ruler subdivisions. RulerN.java takes an integer command-line argument n and prints the string of ruler subdivision lengths. This program illustrates one of the essential characteristics of loops—the program could hardly be simpler, but it can produce a huge amount of output.
Harmonic numbers
Finite sums. The computational paradigm used in PowersOfTwo.java is one that you will use frequently. It uses two variables—one as an index that controls a loop, and the other to accumulate a computational result. Program HarmonicNumber.java uses the same paradigm to evaluate the sum
Hn=11+12+13+14+…+1n
These numbers, which are known as the harmonic numbers, arise frequently in the analysis of algorithms.
Newton’s method. Newton’s methodSqrt.java uses a classic iterative technique known as Newton’s method to compute the square root of a positive number x: Start with an estimate t. If t is equal to x/t (up to machine precision), then t is equal to a square root of x, so the computation is complete. If not, refine the estimate by replacing t with the average of t and x/t. Each time we perform this update, we get closer to the desired answer.
Number conversion. Binary.java prints the binary (base 2) representation of the decimal number typed as the command-line argument. It is based on decomposing the number into a sum of powers of 2. For example, the binary representation of 106 is 11010102, which is the same as saying that 106 = 64 + 32 + 8 + 2. To compute the binary representation of n, we consider the powers of 2 less than or equal to n in decreasing order to determine which belong in the binary decomposition (and therefore correspond to a 1 bit in the binary representation).
Gambler’s ruin. gambler’s ruin Suppose a gambler makes a series of fair $1 bets, starting with $50, and continue to play until she either goes broke or has $250. What are the chances that she will go home with $250, and how many bets might she expect to make before winning or losing? Gambler.java is a simulation that can help answer these questions. It takes three command-line arguments, the initial stake ($50), the goal amount ($250), and the number of times we want to simulate the game.
Prime factorization. Factors.java takes an integer command-line argument n and prints its prime factorization. In contrast to many of the other programs that we have seen (which we could do in a few minutes with a calculator or pencil and paper), this computation would not be feasible without a computer.
Other conditional and loop constructs. To be complete, we consider four more Java constructs related to conditionals and loops. They are used much less frequently than the if, while, and for statements that we’ve been working with, but it is worthwhile to be aware of them.
Break statements. In some situations, we want to immediate exit a loop without letting it run to completion. Java provides the break statement for this purpose. Prime.java takes an integer command-line argument n and prints true if n is prime, and false otherwise. There are two different ways to leave this loop: either the break statement is executed (because n is not prime) or the loop-continuation condiQUITE THE LOLS QUITE THE LOOLLSLLSLSLLSentered at (0, 0) with radius 1.
do-while loop
With Math.random() we get points that are randomly distributed in the 2-by-2 square center at (0, 0). We just generate points in this region until we find one that lies inside the unit disk. We always want to generate at least one point so a do-while loop is most appropriate. We must declare x and y outside the loop since we will want to access their values after the loop terminates.We don’t use the following two flow control statements in this textbook, but include them here for completeness.
Conditional operator. The conditional operator ?: is a ternary operator (three operands) that enables you to embed a conditional within an expression. The three operands are separated by the ? and : symbols. If the first operand (a boolean expression) is true, the result has the value of the second expression; otherwise it has the value of the third expression.
int min = (x < y) ? x : y;
Labeled break and continue statements. The break and continue statements apply to the innermost for or while loop. Sometimes we want to jump out of several levels of nested loops. Java provides the labeled break and labeled continue statements to accomplish this. Here is an example.
Exercises
Write a program AllEqual.java that takes three integer command-line arguments and prints equal if all three are equal, and not equal otherwise.
Write a program RollLoadedDie.java that prints the result of rolling a loaded die such that the probability of getting a 1, 2, 3, 4, or 5 is 1/8 and the probability of getting a 6 is 3/8.
Rewrite TenHellos.java to make a program Hellos.java that takes the number of lines to print as a command-line argument. You may assume that the argument is less than 1000. Hint: consider using i % 10 and i % 100 to determine whether to use “st”, “nd”, “rd”, or “th” for printing the ith Hello.
Write a program FivePerLine.java that, using one for loop and one if statement, prints the integers from 1000 to 2000 with five integers per line. Hint: use the % operator.
Write a program FunctionGrowth.java that prints a table of the values of ln n, n, n ln n, n2, n3, and 2n for n = 16, 32, 64, …, 2048. Use tabs (‘\t’ characters) to line up columns.
What is the value of m and n after executing the following code?
int n = 123456789;
int m = 0;
while (n != 0) {
m = (10 * m) + (n % 10);
n = n / 10;
}
What does the following code print out?
int f = 0, g = 1;
for (int i = 0; i <= 15; i++) {
System.out.println(f);
f = f + g;
g = f – g;
}
Unlike the harmonic numbers, the sum 1/1 + 1/4 + 1/9 + 1/16 + … + 1/n2 does converge to a constant as n grows to infinity. (Indeed, the constant is π2 / 6, so this formula can be used to estimate the value of π.) Which of the following for loops computes this sum? Assume that n is an int initialized to 1000000 and sum is a double initialized to 0.
(a) for (int i = 1; i <= n; i++)
sum = sum + 1 / (i * i);(b) for (int i = 1; i <= n; i++)
sum = sum + 1.0 / i * i;(c) for (int i = 1; i <= n; i++)
sum = sum + 1.0 / (i * i);(d) for (int i = 1; i <= n; i++)
sum = sum + 1 / (1.0 * i * i);
Modify Binary.java to get a program Modify Kary.java that takes a second command-line argument K and converts the first argument to base K. Assume the base is between 2 and 16. For bases greater than 10, use the letters A through F to represent the 11th through 16th digits, respectively.
Write a program code fragment that puts the binary representation of a positive integer n into a String variable s.
Creative Exercises
Ramanujan’s taxi. S. Ramanujan was an Indian mathematician who became famous for his intuition for numbers. When the English mathematician G. H. Hardy came to visit him in the hospital one day, Hardy remarked that the number of his taxi was 1729, a rather dull number. To which Ramanujan replied, “No, Hardy! No, Hardy! It is a very interesting number. It is the smallest number expressible as the sum of two cubes in two different ways.” Verify this claim by writing a program Ramanujan.java that takes an integer command-line argument n and prints all integers less than or equal to n that can be expressed as the sum of two cubes in two different ways – find distinct positive integers a, b, c, and d such that a3 + b3 = c3 + d3. Use four nested for loops.
Now, the license plate 87539319 seems like a rather dull number. Determine why it’s not.Checksums. The International Standard Book Number (ISBN) is a 10 digit code that uniquely specifies a book. The rightmost digit is a checksum digit which can be uniquely determined from the other 9 digits from the condition that d1 + 2d2 + 3d3 + … + 10d10 must be a multiple of 11 (here di denotes the ith digit from the right). The checksum digit d1 can be any value from 0 to 10: the ISBN convention is to use the value X to denote 10. Example: the checksum digit corresponding to 020131452 is 5 since is the only value of d1 between 0 and and 10 for which d1 + 2*2 + 3*5 + 4*4 + 5*1 + 6*3 + 7*1 + 8*0 + 9*2 + 10*0 is a multiple of 11. Write a program ISBN.java that takes a 9-digit integer as a command-line argument, computes the checksum, and prints the 10-digit ISBN number. It’s ok if you don’t print any leading 0s.
Exponential function. Assume that x is a positive variable of type double. Write a program Exp.java that computes e^x using the Taylor series expansion
ex=1+x+x22!+x33+x44!+…
Trigonometric functions. Write two programs Sin.java and Cos.java that compute sin x and cos x using the Taylor series expansions
sinx=x−x33!+x55!−x77!+…
cosx=1−x22!+x44!−x66!+…
Game simulation. In the game show Let’s Make a Deal, a contestant is presented with three doors. Behind one door is a valuable prize, behind the other two are gag gifts. After the contestant chooses a door, the host opens up one of the other two doors (never revealing the prize, of course). The contestant is then given the opportunity to switch to the other unopened door. Should the contestant do so? Intuitively, it might seem that the contestant’s initial choice door and the other unopened door are equally likely to contain the prize, so there would be no incentive to switch. Write a program MonteHall.java to test this intuition by simulation. Your program should take an integer command-line argument n, play the game n times using each of the two strategies (switch or don’t switch) and print the chance of success for each strategy. Or you can play the game here.
Euler’s sum-of-powers conjecture. In 1769 Leonhard Euler formulated a generalized version of Fermat’s Last Theorem, conjecturing that at least n nth powers are needed to obtain a sum that is itself an nth power, for n > 2. Write a program Euler.java to disprove Euler’s conjecture (which stood until 1967), using a quintuply nested loop to find four positive integers whose 5th power sums to the 5th power of another positive integer. That is, find a, b, c, d, and e such that a5 + b5 + c5 + d5 = e5. Use the long data type.
Web Exercises
Write a program RollDie.java that generates the result of rolling a fair six-sided die (an integer between 1 and 6).
Write a program that takes three integer command-line arguments a, b, and c and print the number of distinct values (1, 2, or 3) among a, b, and c.
Write a program that takes five integer command-line arguments and prints the median (the third largest one).
(hard) Now, try to compute the median of 5 elements such that when executed, it never makes more than 6 total comparisons.
How can I create in an infinite loop with a for loop?
Solution: for(;;) is the same as while(true).What’s wrong with the following loop?
boolean done = false;
while (done = false) {
…
}
The while loop condition uses = instead of == so it is an assignment statement (which makes done always false and the body of the loop will never be executed). It’s better to style to avoid using ==.
boolean done = false;
while (!done) {
…
}
What’s wrong with the following loop that is intended to compute the sum of the integers 1 through 100?
for (int i = 1; i <= N; i++) {
int sum = 0;
sum = sum + i;
}
System.out.println(sum);
The variable sum should be defined outside the loop. By defining it inside the loop, a new variable sum is initialized to 0 each time through the loop; also it is not even accessible outside the loop.
Write a program Hurricane.java that that takes the wind speed (in miles per hour) as an integer command-line argument and prints whether it qualifies as a hurricane, and if so, whether it is a Category 1, 2, 3, 4, or 5 hurricane. Below is a table of the wind speeds according to the Saffir-Simpson scale.
CategoryWind Speed (mph)
174 – 95
296 – 110
3111 – 130
4131 – 155
5155 and above
What is wrong with the following code fragment?
double x = -32.2;
boolean isPositive = (x > 0);
if (isPositive = true) System.out.println(x + ” is positive”);
else System.out.println(x + ” is not positive”);
Solution: It uses the assignment operator = instead of the equality operator ==. A better solution is to write if (isPositive).Change/add one character so that the following program prints 20 xs. There are two different solutions.
int i = 0, n = 20;
for (i = 0; i < n; i–)
System.out.print(“x”);
Solution: Replace the i < n condition with -i < n. Replace the i– with n–. ( In C, there is a third: replace the < with a +.)
What does the following code fragment do?
if (x > 0);
System.out.println(“positive”);
Solution: always prints positive regardless of the value of x because of the extra semicolon after the if statement.RGB to HSB converter. Write a program RGBtoHSV.java that takes an RGB color (three integers between 0 and 255) and transforms it to an HSB color (three different integers between 0 and 255). Write a program HSVtoRGB.java that applies the inverse transformation.
Boys and girls. A couple beginning a family decides to keep having children until they have at least one of either sex. Estimate the average number of children they will have via simulation. Also estimate the most common outcome (record the frequency counts for 2, 3, and 4 children, and also for 5 and above). Assume that the probability p of having a boy or girl is 1/2.
What does the following program do?
public static void main(String[] args) {
int N = Integer.parseInt(args[0]);
int x = 1;
while (N >= 1) {
System.out.println(x);
x = 2 * x;
N = N / 2;
}
}
Solution: Prints all of the powers of 2 less than or equal to n.
Boys and girls. Repeat the previous question, but assume the couple keeps having children until they have another child which is of the same sex as the first child. How does your answer change if p is different from 1/2?
Surprisingly, the average number of children is 2 if p = 0 or 1, and 3 for all other values of p. But the most likely value is 2 for all values of p.Given two positive integers a and b, what result does the following code fragment leave in c
c = 0;
while (b > 0) {
if (b % 2 == 1) c = c + a;
b = b / 2;
a = a + a;
}
Solution: a * b.Write a program using a loop and four conditionals to print
12 midnight
1am
2am
…
12 noon
1pm
…
11pm
What does the following program print?
public class Test {
public static void main(String[] args) {
if (10 > 5);
else; {
System.out.println(“Here”);
};
}
}
Alice tosses a fair coin until she sees two consecutive heads. Bob tosses another fair coin until he sees a head followed by a tail. Write a program to estimate the probability that Alice will make fewer tosses than Bob? Solution: 39/121.
Rewrite DayOfWeek.java from Exercise 1.2.29 so that it prints the day of the week as Sunday, Monday, and so forth instead of an integer between 0 and 6. Use a switch statement.
Number-to-English. Write a program to read in a command line integer between -999,999,999 and 999,999,999 and print the English equivalent. Here is an exhaustive list of words that your program should use: negative, zero, one, two, three, four, five, six, seven, eight, nine, ten, eleven, twelve, thirteen, fourteen, fifteen, sixteen, seventeen, eighteen, nineteen, twenty, thirty, forty, fifty, sixty, seventy, eighty, ninety, hundred, thousand, million . Don’t use hundred, when you can use thousand, e.g., use one thousand five hundred instead of fifteen hundred. Reference.
Gymnastics judging. A gymnast’s score is determined by a panel of 6 judges who each decide a score between 0.0 and 10.0. The final score is determined by discarding the high and low scores, and averaging the remaining 4. Write a program GymnasticsScorer.java that takes 6 real command line inputs representing the 6 scores and prints their average, after throwing out the high and low scores.
Quarterback rating. To compare NFL quarterbacks, the NFL devised a the quarterback rating formula based on the quarterbacks number of completed passes (A), pass attempts (B), passing yards (C), touchdown passes (D), and interception (E) as follows:
Completion ratio: W = 250/3 * ((A / B) – 0.3).
Yards per pass: X = 25/6 * ((C / B) – 3).
Touchdown ratio: Y = 1000/3 * (D / B)
Interception ratio: Z = 1250/3 * (0.095 – (E / B))
The quarterback rating is computed by summing up the above four quantities, but rounding up or down each value so that it is at least 0 and and at most 475/12. Write a program QuarterbackRating.java that takes five command line inputs A, B, C, D, and E, and prints the quarterback rating. Use your program to compute Steve Young’s 1994 record-setting season (112.8) in which he completed 324 of 461 passes for 3,969 yards, and threw 35 touchdowns and 10 interceptions. As of 2014, the all-time single-season record is 122.5 by Aaron Rodgers in 2011.
Decimal expansion of rational numbers. Given two integers p and q, the decimal expansion of p/q has an infinitely repeating cycle. For example, 1/33 = 0.03030303…. We use the notation 0.(03) to denote that 03 repeats indefinitely. As another example, 8639/70000 = 0.1234(142857). Write a program DecimalExpansion.java that reads in two command line integers p and q and prints the decimal expansion of p/q using the above notation. Hint: use Floyd’s rule.
Friday the 13th. What is the maximum number of consecutive days in which no Friday the 13th occurs? Hint: The Gregorian calendar repeats itself every 400 years (146097 days) so you only need to worry about a 400 year interval.
Solution: 426 (e.g., from 8/13/1999 to 10/13/2000).January 1. Is January 1 more likely to fall on a Saturday or Sunday? Write a program to determine the number of times each occurs in a 400 year interval.
Solution: Sunday (58 times) is more likely than Saturday (56 times).What do the following two code fragments do?
for (int i = 0; i < N; i++)
for (int j = 0; j < N; j++)
if (i != j) System.out.println(i + “, ” + j);for (int i = 0; i < N; i++)
for (int j = 0; (i != j) && (j < N); j++)
System.out.println(i + “, ” + j);
Determine what value gets printed out without using a computer. Choose the correct answer from 0, 100, 101, 517, or 1000.
int cnt = 0;
for (int i = 0; i < 10; i++)
for (int j = 0; j < 10; j++)
for (int k = 0; k < 10; k++)
if (2*i + j >= 3*k)
cnt++;
System.out.println(cnt);
Rewrite CarLoan.java from Creative Exercise XYZ so that it properly handles an interest rate of 0% and avoids dividing by 0.
Write the shortest Java program you can that takes an integer command-line argument n and prints true if (1 + 2 + … + n) 2 is equal to (13 + 23 + … + n3).
Solution: Always print true.Modify Sqrt.java so that it reports an error if the user enters a negative number and works properly if the user enters zero.
What happens if we initialize t to -x instead of x in program Sqrt.java?
Sample standard deviation of uniform distribution. Modify Exercise 8 so that it prints the sample standard deviation in addition to the average.
Sample standard deviation of normal distribution. that takes an integer N as a command-line argument and uses Web Exercise 1 from Section 1.2 to print N standard normal random variables, and their average value, and sample standard deviation.
Loaded dice. [Stephen Rudich] Suppose you have three, three sided dice. A: {2, 6, 7}, B: { 1, 5, 9}, and C: {3, 4, 8}. Two players roll a die and the one with the highest value wins. Which die would you choose? Solution: A beats B with probability 5/9, B beats C with probability 5/9 and C beats A with probability 5/9. Be sure to choose second!
Thue–Morse sequence. Write a program ThueMorse.java that reads in a command line integer n and prints the Thue–Morse sequence of order n. The first few strings are 0, 01, 0110, 01101001. Each successive string is obtained by flipping all of the bits of the previous string and concatenating the result to the end of the previous string. The sequence has many amazing properties. For example, it is a binary sequence that is cube-free: it does not contain 000, 111, 010101, or sss where s is any string. It is self-similar: if you delete every other bit, you get another Thue–Morse sequence. It arises in diverse areas of mathematics as well as chess, graphic design, weaving patterns, and music composition.
Program Binary.java prints the binary representation of a decimal number n by casting out powers of 2. Write an alternate version Program Binary2.java that is based on the following method: Write 1 if n is odd, 0 if n is even. Divide n by 2, throwing away the remainder. Repeat until n = 0 and read the answer backwards. Use % to determine whether n is even, and use string concatenation to form the answer in reverse order.
What does the following code fragment do?
int digits = 0;
do {
digits++;
n = n / 10;
} while (n > 0);
Solution: The number of bits in the binary representation of a natural number n. We use a do-while loop so that code output 1 if n = 0.Write a program NPerLine.java that takes an integer command-line argument n and prints the integers from 10 to 99 with n integers per line.
Modify NPerLine.java so that it prints the integers from 1 to 1000 with n integers per line. Make the integers line up by printing the right number of spaces before an integer (e.g., three for 1-9, two for 10-99, and one for 100-999).
Suppose a, b, and c are random number uniformly distributed between 0 and 1. What is the probability that a, b, and c form the side length of some triangle? Hint: they will form a triangle if and only if the sum of every two values is larger than the third.
Repeat the previous question, but calculate the probability that the resulting triangle is obtuse, given that the three numbers for a triangle. Hint: the three lengths will form an obtuse triangle if and only if (i) the sum of every two values is larger than the third and (ii) the sum of the squares of every two side lengths is greater than or equal to the square of the third.
Answer.What is the value of s after executing the following code?
int M = 987654321;
String s = “”;
while (M != 0) {
int digit = M % 10;
s = s + digit;
M = M / 10;
}
What is the value of i after the following confusing code is executed?
int i = 10;
i = i++;
i = ++i;
i = i++ + ++i;
Moral: don’t write code like this.Formatted ISBN number. Write a program ISBN2.java that reads in a 9 digit integer from a command-line argument, computes the check digit, and prints the fully formatted ISBN number, e.g, 0-201-31452-5.
UPC codes. The Universal Product Code (UPC) is a 12 digit code that uniquely specifies a product. The least significant digit d1(rightmost one) is a check digit which is the uniquely determined by making the following expression a multiple of 10:
(d1 + d3 + d5 + d7 + d9 + d11) + 3 (d2 + d4 + d6 + d8 + d10 + d12)
As an example, the check digit corresponding to 0-48500-00102 (Tropicana Pure Premium Orange Juice) is 8 since(8 + 0 + 0 + 0 + 5 + 4) + 3 (2 + 1 + 0 + 0 + 8 + 0) = 50
and 50 is a multiple of 10. Write a program that reads in a 11 digit integer from a command line parameter, computes the check digit, and prints the the full UPC. Hint: use a variable of type long to store the 11 digit number.Write a program that reads in the wind speed (in knots) as a command line argument and prints its force according to the Beaufort scale. Use a switch statement.
Making change. Write a program that reads in a command line integer N (number of pennies) and prints the best way (fewest number of coins) to make change using US coins (quarters, dimes, nickels, and pennies only). For example, if N = 73 then print
2 quarters
2 dimes
3 pennies
Hint: use the greedy algorithm. That is, dispense as many quarters as possible, then dimes, then nickels, and finally pennies.Write a program Triangle.java that takes a command-line argument N and prints an N-by-N triangular pattern like the one below.
* * * * * *
. * * * * *
. . * * * *
. . . * * *
. . . . * *
. . . . . *
Write a program Ex.java that takes a command-line argument N and prints a (2N + 1)-by-(2N + 1) ex like the one below. Use two for loops and one if-else statement.
* . . . . . *
. * . . . * .
. . * . * . .
. . . * . . .
. . * . * . .
. * . . . * .
* . . . . . *
Write a program BowTie.java that takes a command-line argument N and prints a (2N + 1)-by-(2N + 1) bowtie like the one below. Use two for loops and one if-else statement.
* . . . . . *
* * . . . * *
* * * . * * *
* * * * * * *
* * * . * * *
* * . . . * *
* . . . . . *
Write a program Diamond.java that takes a command-line argument N and prints a (2N + 1)-by-(2N + 1) diamond like the one below.
% java Diamond 4
. . . . * . . . .
. . . * * * . . .
. . * * * * * . .
. * * * * * * * .
* * * * * * * * *
. * * * * * * * .
. . * * * * * . .
. . . * * * . . .
. . . . * . . . .
Write a program Heart.java that takes a command-line argument N and prints a heart.
What does the program Circle.java print out when N = 5?
for (int i = -N; i <= N; i++) {
for (int j = -N; j <= N; j++) {
if (i*i + j*j <= N*N) System.out.print(“* “);
else System.out.print(“. “);
}
System.out.println();
}
Seasons. Write a program Season.java that takes two command line integers M and D and prints the season corresponding to month M (1 = January, 12 = December) and day D in the northern hemisphere. Use the following table
SEASONFROMTO
SpringMarch 21June 20
SummerJune 21September 22
FallSeptember 23December 21
WinterDecember 21March 20Zodiac signs. Write a program Zodiac.java that takes two command line integers M and D and prints the Zodiac sign corresponding to month M (1 = January, 12 = December) and day D. Use the following table
SIGNFROMTO
CapricornDecember 22January 19
AquariusJanuary 20February 17
PiscesFebruary 18March 19
AriesMarch 20April 19
TaurusApril 20May 20
GeminiMay 21June 20
CancerJune 21July 22
LeoJuly 23August 22
VirgoAugust 23September 22
LibraSeptember 23October 22
ScorpioOctober 23November 21
SagittariusNovember 22December 21
Muay Thai kickboxing. Write a program that reads in the weight of a Muay Thai kickboxer (in pounds) as a command-line argument and prints their weight class. Use a switch statement.
CLASSFROMTO
Flyweight0112
Super flyweight112115
Bantamweight115118
Super bantamweight118122
Featherweight122126
Super featherweight126130
Lightweight130135
Super lightweight135140
Welterweight140147
Super welterweight147154
Middleweight154160
Super middleweight160167
Light heavyweight167175
Super light heavyweight175183
Cruiserweight183190
Heavyweight190220
Super heavyweight220-
Euler’s sum of powers conjecture. In 1769 Euler generalized Fermat’s Last Theorem and conjectured that it is impossible to find three 4th powers whose sum is a 4th power, or four 5th powers whose sum is a 5th power, etc. The conjecture was disproved in 1966 by exhaustive computer search. Disprove the conjecture by finding positive integers a, b, c, d, and e such that a5 + b5 + c5 + d5= e5. Write a program Euler.java that reads in a command line parameter N and exhaustively searches for all such solutions with a, b, c, d, and e less than or equal to N. No counterexamples are known for powers greater than 5, but you can join EulerNet, a distributed computing effort to find a counterexample for sixth powers.
Blackjack. Write a program Blackjack.java that takes three command line integers x, y, and z representing your two blackjack cards x and y, and the dealers face-up card z, and prints the “standard strategy” for a 6 card deck in Atlantic city. Assume that x, y, and z are integers between 1 and 10, representing an ace through a face card. Report whether the player should hit, stand, or split according to these strategy tables. (When you learn about arrays, you will encounter an alternate strategy that does not involve as many if-else statements).
Blackjack with doubling. Modify the previous exercise to allow doubling.
Projectile motion. The following equation gives the trajectory of a ballistic missile as a function of the initial angle theta and windspeed: xxxx. Write a java program to print the (x, y) position of the missile at each time step t. Use trial and error to determine at what angle you should aim the missile if you hope to incinerate a target located 100 miles due east of your current location and at the same elevation. Assume the windspeed is 20 mph due east.
World series. The baseball world series is a best of 7 competition, where the first team to win four games wins the World Series. Suppose the stronger team has probability p > 1/2 of winning each game. Write a program to estimate the chance that the weaker teams wins the World Series and to estimate how many games on average it will take.
Consider the equation (9/4)^x = x^(9/4). One solution is 9/4. Can you find another one using Newton’s method?
Sorting networks. Write a program Sort3.java with three if statements (and no loops) that reads in three integers a, b, and c from the command line and prints them out in ascending order.
if (a > b) swap a and b
if (a > c) swap a and c
if (b > c) swap b and c
Oblivious sorting network. Convince yourself that the following code fragment rearranges the integers stored in the variables A, B, C, and D so that A <= B <= C <= D.
if (A > B) { t = A; A = B; B = t; }
if (B > C) { t = B; B = C; C = t; }
if (A > B) { t = A; A = B; B = t; }
if (C > D) { t = C; C = D; D = t; }
if (B > C) { t = B; B = C; C = t; }
if (A > B) { t = A; A = B; B = t; }
if (D > E) { t = D; D = E; E = t; }
if (C > D) { t = C; C = D; D = t; }
if (B > C) { t = B; B = C; C = t; }
if (A > B) { t = A; A = B; B = t; }
Devise a sequence of statements that would sort 5 integers. How many if statements does your program use?
Optimal oblivious sorting networks. Create a program that sorts four integers using only 5 if statements, and one that sorts five integers using only 9 if statements of the type above? Oblivious sorting networks are useful for implementing sorting algorithms in hardware. How can you check that your program works for all inputs?
Solution: Sort4.java sorts 4 elements using 5 compare-exchanges. Sort5.java sorts 5 elements using 9 compare-exchanges.The 0-1 principle asserts that you can verify the correctness of a (deterministic) sorting algorithm by checking whether it correctly sorts an input that is a sequence of 0s and 1s. Thus, to check that Sort5.java works, you only need to test it on the 2^5 = 32 possible inputs of 0s and 1s.
Optimal oblivious sorting (challenging). Find an optimal sorting network for 6, 7, and 8 inputs, using 12, 16, and 19 if statements of the form in the previous problem, respectively.
Solution: Sort6.java is the solution for sorting 6 elements.Optimal non-oblivious sorting. Write a program that sorts 5 inputs using only 7 comparisons. Hint: First compare the first two numbers, the second two numbers, and the larger of the two groups, and label them so that a < b < d and c < d. Second, insert the remaining element e into its proper place in the chain a < b < d by first comparing against b, then either a or d depending on the outcome. Third, insert c into the proper place in the chain involving a, b, d, and e in the same manner that you inserted e (with the knowledge that c < d). This uses 3 (first step) + 2 (second step) + 2 (third step) = 7 comparisons. This method was first discovered by H. B. Demuth in 1956.
Weather balloon. (Etter and Ingber, p. 123) Suppose that h(t) = 0.12t4 + 12t3 – 380t2 + 4100t + 220 represents the height of a weather balloon at time t (measured in hours) for the first 48 hours after its launch. Create a table of the height at time t for t = 0 to 48. What is its maximum height? Solution: t = 5.
Will the following code fragment compile? If so, what will it do?
int a = 10, b = 18;
if (a = b) System.out.println(“equal”);
else System.out.println(“not equal”);
Solution: It uses the assignment operator = instead of the equality operator == in the conditional. In Java, the result of this statement is an integer, but the compiler expects a boolean. As a result, the program will not compile. In some languages (notably C and C++), this code fragment will set the variable a to 18 and print equal without an error.Gotcha 1. What does the following code fragment do?
boolean a = false;
if (a = true) System.out.println(“yes”);
else System.out.println(“no”);
Solution: it prints yes. Note that the conditional uses = instead of ==. This means that a is assigned the value true As a result, the conditional expression evaluates to true. Java is not immune to the = vs. == error described in the previous exercise. For this reason, it is much better style to use if (a) or if (!a) when testing booleans.
Gotcha 2. What does the following code fragment do?
int a = 17, x = 5, y = 12;
if (x > y);
{
a = 13;
x = 23;
}
System.out.println(a);
Solution: Always prints 13 since there is a spurious semicolon after the if statement. Thus, the assignment statement a = 13; will be executed even though (x <= y) It is legal (but uncommon) to have a block that does not belong to a conditional statement, loop, or method.
Gotcha 3. What does the following code fragment do?
for (int x = 0; x < 100; x += 0.5) {
System.out.println(x);
}
Solution: It goes into an infinite loop printing 0. The compound assignment statement x += 0.5 is equivalent to x = (int) (x + 0.5).
What does the following code fragment do?
int income = Integer.parseInt(args[0]);
if (income >= 311950) rate = .35;
if (income >= 174700) rate = .33;
if (income >= 114650) rate = .28;
if (income >= 47450) rate = .25;
if (income >= 0) rate = .22;
System.out.println(rate);
It does not compile because the compile cannot guarantee that rate is initialized. Use if-else instead.
Application of Newton’s method. Write a program BohrRadius.java that finds the radii where the probability of finding the electron in the 4s excited state of hydrogen is zero. The probability is given by: (1 – 3r/4 + r2/8 – r3/192)2 e-r/2, where r is the radius in units of the Bohr radius (0.529173E-8 cm). Use Newton’s method. By starting Newton’s method at different values of r, you can discover all three roots. Hint: use initial values of r= 0, 5, and 13. Challenge: explain what happens if you use an initial value of r = 4 or 12.
Pepys problem. In 1693, Samuel Pepys asked Isaac Newton which was more likely: getting at least one 1 when rolling a fair die 6 times or getting at least two 1’s when rolling a fair die 12 times. Write a program Pepys.java that uses simulation to determine the correct answer.
What is the value of the variable s after running the following loop when N = 1, 2, 3, 4, and 5.
String s = “”;
for (int i = 1; i <= N; i++) {
if (i % 2 == 0) s = s + i + s;
else s = i + s + i;
}
Solution: Palindrome.java.Body mass index. The body mass index (BMI) is the ratio of the weight of a person (in kilograms) to the square of the height (in meters). Write a program BMI.java that takes two command-line arguments, weight and height, computes the BMI, and prints the corresponding BMI category:
Starvation: less than 15
Anorexic: less than 17.5
Underweight: less than 18.5
Ideal: greater than or equal to 18.5 but less than 25
Overweight: greater than or equal to 25 but less than 30
Obese: greater than or equal to 30 but less than 40
Morbidly Obese: greater than or equal to 40
Reynolds number. The Reynolds number is the ratio if inertial forces to viscous forces and is an important quantity in fluid dynamics. Write a program that takes in 4 command-line arguments, the diameter d, the velocity v, the density rho, and the viscosity mu, and prints the Reynold’s number d * v * rho / mu (assuming all arguments are in SI units). If the Reynold’s number is less than 2000, print laminar flow, if it’s between 2000 and 4000, print transient flow, and if it’s more than 4000, print turbulent flow.
Wind chill revisited. The wind chill formula from Exercise 1.2.14 is only valid if the wind speed is above 3MPH and below 110MPH and the temperature is below 50 degrees Fahrenheit and above -50 degrees. Modify your solution to print an error message if the user types in a value outside the allowable range.
Point on a sphere. Write a program to print the (x, y, z) coordinates of a random point on the surface of a sphere. Use Marsaglia’ method: pick a random point (a, b) in the unit circle as in the do-while example. Then, set x = 2a sqrt(1 – a^2 – b^2), y = 2b sqrt(1 – a^2 – b^2), z = 1 – 2(a^2 + b^2).
Powers of k. Write a program PowersOfK.java that takes an integer K as command-line argument and prints all the positive powers of K in the Java long data type. Note: the constant Long.MAX_VALUE is the value of the largest integer in long.
Square root, revisited. Why not use the loop-continuation condition (Math.abs(t*t – c) > EPSILON) in Sqrt.java instead of Math.abs(t – c/t) > t*EPSILON)?
Solution: Surprisingly, it can lead to inaccurate results or worse. For example, if you supply SqrtBug.java with the command-line argument 1e-50, you get 1e-50 as the answer (instead of 1e-25); if you supply 16664444, you get an infinite loop!What happens when you try to compile the following code fragment?
double x;
if (a >= 0) x = 3.14;
if (a < 0) x = 2.71;
System.out.println(x);
Solution: It complains that the variable x might not have been initialized (even though we can clearly see that x will be initialized by one of the two if statements). You can avoid this problem here by using if-else.Last modified on October 02, 2017.
Copyright © 2000–2018 Robert Sedgewick and Kevin Wayne. All rights reserved.
WHO CLASSIFICATION OF HEAD AND NECK TUMOURS 1
C00-C06, C09-C10, C14 – Lip, Oral Cavity and Oropharynx:Malignant epithelial tumors
Benign epithelial tumors
Salivary gland tumors
Soft tissue tumors
Haematolymphoid tumorsMalignant epithelial tumors
8070/3 Squamous cell carcinoma, NOS
8051/3 Verrucous carcinoma, NOS
8083/3 Basaloid squamous cell carcinoma
8052/3 Papillary squamous cell carcinoma
8074/3 Squamous cell carcinoma, spindle cell
8075/3 Squamous cell carcinoma, adenoid
8560/3 Adenosquamous carcinoma
8082/3 Lymphoepithelial carcinoma
8082/3 Schmincke tumorBenign epithelial tumors
8050/0 Papilloma, NOS
9580/0 Granular cell tumor, NOSSalivary gland tumors
Salivary gland carcinomas
8550/3 Acinar cell carcinoma
8430/3 Mucoepidermoid carcinoma
8200/3 Adenoid cystic carcinoma
8200/3 Bronchial adenoma, cylindroid
8525/3 Polymorphous low grade adenocarcinoma
8147/3 Basal cell adenocarcinoma
8562/3 Epithelial-myoepithelial carcinoma
8310/3 Clear cell adenocarcinoma, NOS
8310/3 Clear cell adenocarcinoma, mesonephroid
8450/3 Papillary cystadenocarcinoma, NOS
8480/3 Mucinous adenocarcinoma
8480/3 Pseudomyxoma peritonei with unknown primary site
8290/3 Oxyphilic adenocarcinoma
8290/3 Hurthle cell carcinoma
8290/3 Hurthle cell adenocarcinoma
8290/3 Follicular carcinoma, oxyphilic cell
8500/3 Infiltrating duct carcinoma, NOS
8982/3 Malignant myoepithelioma
8941/3 Carcinoma in pleomorphic adenomaSalivary gland adenomas
8940/0 Pleomorphic adenoma
8940/0 Chondroid syringoma
8982/0 Myoepithelioma
8147/0 Basal cell adenoma
8149/0 Canalicular adenoma
8503/0 Intraductal papilloma
8440/0 Cystadenoma, NOSSoft tissue tumors
9140/3 Kaposi sarcoma
9170/0 Lymphangioma, NOSHaematolymphoid tumors
9673/3 Mantle cell lymphoma
9690/3 Follicular lymphoma, NOS
9687/3 Burkitt lymphoma, NOS
9687/3 Burkitt-like lymphoma
9734/3 Plasmacytoma, extramedullary
9930/3 Myeloid sarcoma
9758/3 Follicular dendritic cell sarcoma
9758/3 Follicular dendritic cell tumor8720/3 Malignant melanoma, NOS
IARC, 150 Cours Albert Thomas, 69372 Lyon CEDEX 08, France – Tel: +33 (0)4 72 73 84 85
© IARC 2018 – All Rights Reserved.
9673/3 MANTLE CELL LYMPHOMASynonyms
Mantle zone lymphoma
Malignant lymphoma, lymphocytic, intermediate differentiation, diffuse
Malignant lymphoma, centrocytic
Malignant lymphomatous polyposisDefinitions
Small intestine
ICD-O-3 topography code:C17
ICD10:C83.1Mantle cell lymphoma (MCL) is an aggressive, usually diffuse non-Hodgkin lymphoma composed of monomorphic small to medium sized B-lymphocytes (centrocytes). The t(11;14)(q13;q32) translocation causes an overexpression of cyclin D1 (CCND1), is present in almost all cases and considered the primary genetic event 1 . MCL manisfests preferentially in middle-aged to older male patients with advanced stage disease with lymphadenopathy, hepatosplenomegaly, and bone marrow involvement. The gastrointestinal tract is the most commonly affected extranodal site, occasionally as lymphomatous polyposis.
Tumours of haematopoietic and lymphoid tissues
ICD-O-3 topography code:C42 and C77
ICD10:C83.1/span>antle cell lymphoma (MCL) is a B-cell neoplasm generally composed of mono?morphic small to medium-sized lymphoid cells with irregular nuclear contours and a CCND1 translocation 2 3 4 5 6 7 8 . Neoplastic trans?formed cells (centroblasts), paraimmuno?blasts and proliferation centres are absent.
>
Lip, Oral Cavity and Oropharynx
ICD-O-3 topography code:C00-C06, C09-C10, C14
ICD10:C83.1Mantle cell lymphoma (MCL) is an aggressive, usually diffuse non-Hodgkin lymphoma composed of monomorphic small to medium sized B-lymphocytes (centrocytes). The t(11;14)(q13;q32) translocation causes an overexpression of cyclin D1 (CCND1), is present in almost all cases and considered the primary genetic event 10 .
MCL manisfests preferentially in middle-aged to older male patients with advanced stage disease with lymphadenopathy, hepatosplenomegaly, and bone marrow involvement. The gastrointestinal tract is the most commonly affected extranodal site, occasionally as
lymphomatous polyposis.Colon and rectum
ICD-O-3 topography code:C18-C20
ICD10:C83.1Mantle cell lymphoma (MCL) is an aggressive, usually diffuse non-Hodgkin lymphoma composed of monomorphic small to medium sized B-lymphocytes (centrocytes). The t(11;14)(q13;q32) translocation causes an overexpression of cyclin D1 (CCND1), is present in almost all cases and considered the primary genetic event 11 . MCL manisfests preferentially in middle-aged to older male patients with advanced stage disease with lymphadenopathy, hepatosplenomegaly, and bone marrow involvement. The gastrointestinal tract is the most commonly affected extranodal site, occasionally as lymphomatous polyposis.
Stomach
ICD-O-3 topography code:C16
ICD10:C83.1Mantle cell lymphoma (MCL) is an aggressive, usually diffuse non-Hodgkin lymphoma composed of monomorphic small to medium sized B-lymphocytes (centrocytes). The t(11;14)(q13;q32) translocation causes an overexpression of cyclin D1 (CCND1), is present in almost all cases and considered the primary genetic event 12 .
MCL manifests preferentially in middle-aged to older male patients with advanced stage disease with lymphadenopathy, hepatosplenomegaly, and bone marrow involvement. The gastrointestinal tract is the most commonly affected extranodal site, occasionally as lymphomatous polyposis.Skin
ICD-O-3 topography code:C44
ICD10:C83.1Mantle cell lymphoma (MCL) is an aggressive, usually diffuse non-Hodgkin lymphoma composed of monomorphic small to medium sized B-lymphocytes (centrocytes). The t(11;14)(q13;q32) translocation causes an overexpression of cyclin D1 (CCND1), is present in almost all cases and considered the primary genetic event 13 .
MCL manisfests preferentially in middle-aged to older male patients with advanced stage disease with lymphadenopathy, hepatosplenomegaly, and bone marrow involvement. The gastrointestinal tract is the most commonly affected extranodal site, occasionally as
lymphomatous polyposis.IARC, 150 Cours Albert Thomas, 69372 Lyon CEDEX 08, France – Tel: +33 (0)4 72 73 84 85
© IARC 2018 – All Rights Reserved.The southern study area in the Xishuangbanna prefecture of China’s Yunnan Province is located
between 22°00’N–23°50’00″N and 100°00’12″E–102°00’E and covers about 50,000 ha (Figure 1). It
belongs to the lower catchment of the Lancang River. Xishuangbanna is home to the richest biological
and ethnic diversity (i.e., Thai, Lahu, Jinuo, and Jingpo people) in China. The maximum altitude is
about 2,000 m. The climate of the region is strongly seasonal. The monthly average temperature ranges
between 16.4°C and 22.0 °C. Between May and October the South-West Monsoon air masses brings
about 80% of annual rainfall, whereas the dry and cold air of the Southern edges of the jet stream
dominates the weather pattern between November and April. Annual rainfall varies between 1,200 mm
in the Lancang valley and 1,900 mm at altitudes above 1,500 m.
Remote Sens. 2014, 6 1030
2.2. Software
Canoco 4.5 was used to perform ordination. ArcView 3.2 and ArcGIS 9.1 were used to calculate
topographic attributes and to perform ordinary kriging. Artificial Neural Networks (ANN)
classification was conducted with LNNS, a neural network simulation program developed at the
Laboratory of Forest Management and Spatial Information Techniques (FORSIT), Ghent University,
Belgium. LNNS is freely available at http://dfwm.ugent.be/forsit [55]. Idrisi Andes was used to assess
accuracy comparison between different classification strategies.
2.3. Data
2.3.1. Image Data
Each study area is covered by a 30 m resolution Landsat Thematic Mapper 5 (TM) image (Table 1).
The available Landsat images are third level products of the China Remote Sensing Satellite Ground
Station (http://www.rsgs.ac.cn/English/Standard%20Product.htm). Basic radiometric and geometric
preprocessing was done by the image provider. Gitas and Devereux (2006) [56] mentioned that
topographic correction should be regarded as an essential elFrom the horses mouth:
Satellite Data CodesSatellite Data Codes are used by telemetry stations, forecast centers and others to encode solar geophysical data obtained from satellite-based sensors.USXRA CodesSolar x-ray events..
Example:
Definition of symbols:
USXRA comes from Solar X-RAy events
I I I I I = station indicator
Y = last digit of yearMM = month of year, 01 = January, 02 = February, etc. DD = UT day of month
SS = satellite06 = GOES-607 = GOES-708 = GOES-809 = GOES-9E = energy range1 = .1-.8 nmNN = number of events
0 = indicates that the begin time of the event followsHHmm = UT hour and minute of beginning of event
0 = indicates that the maximum time of the event followsHHmm = UT hour and minute of maximum for event
0 = indicates that the the end time of the event followsHHmm = UT hour and minute of end time of event
Maximum Flux:Q = qualifier0 = uncertain data1 = certain dataab = x-ray flux in Wm-1 where ab = a.bS = sign of the exponent to apply to a.b0 = positive1 = negativep = power of ten to apply to a.bNote: abSp reported as 4192 would equal 4.1 x 10-1Wm-1
Note: / is to be used for data not available.
Integrated flux (start thru end):9 = qualifierab x-ray integrated flux in Jm-1 where ab = a.bS = sign of the exponent to apply to a.b0 = positive1 = negativep = power of ten to apply to a.bNote: abSp reported as 5692 would equal 5.6 x 10-1Wm-1
Note: / is to be used for data not available.
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MembersSpace Weather NowSpace Weather EffectsSatellitesAviationsNavigationsPower GridsCommunicationsExamples
URSIgram CodesGeophysical Data CodesAlerts, Analasys & Forecasts CodesRadio Data CodesOptical Data CodesSatellite Data CodesSatellite Ionospheric Data CodesRWC and Specialized CodesUhh..this is not an argument…and these satellite codes prove what? That satellites have a framework of language that exist through other frameworks of languages (numbers and English alphabet)? It just proves my point.

Some people know what this is. I will make it my new hobby. MEOW! LOL
Encrypted GPS
GPS was developed by the Defense Department primarily for military purposes. And even though it’s been estimated that there are ten times as many civilian receivers as military ones the system still has considerable military significance.
To that end the military maintains exclusive access to the more accurate “P-code” pseudo random code. It’s ten times the frequency of the civilian C/A code (and so potentially much more accurate) and much harder to jam. When it’s encrypted it’s called “Y-code” and only military receivers with the encryption key can receive it. Because this code is modulated on two carriers, sophisticated games can be played with the frequencies to help eliminate errors caused by the atmosphere.
Its a shot across the bow you f~~~ing s~~~christ bitch. DO not f~~~ with me
And the schizophrenic projection occurs again.
Go ahead and post as much as you want, a shot across the bow is just another way of rationalizing the fact you missed the point.
All the biological examples are merely classifications of specific parts, with the parts existing relative and through other parts (such as the heart exists through the body while existing through the framework of veins and muscles with veins and muscles existing through the heart). One framework is composed of a another.
Relative to sports they are strictly classifications of weight class where boxing exists through various weight class (which change relative to time and circumstance) and these weight classes as frameworks are effectively nothing without the framework of boxing as a set of rules.
Relative to computer languages they are composed of various fields of mathematics, such as type theory or lambda calculus, while the languages themselves change over time relative to not just break through in mathematics and logic (or even physics with quantum computing) but standard language as well. They are all interlinked frameworks with a change in one framework changing in another.
Geographic positions change with time as well as the boundaries due to socio political change.
And so on and so forth. Thw argument is universal and infinite and applies to all phenomenon in infinite variation.
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/****************************************************************/
/* */
/* ********* ** ** ******* ********* ** ** */
/* ********* **** ** ******* ********* ** ** */
/* ** ** ** ** ** ** ** ** ** */
/* ** ** ** ** ** ** ** **** */
/* ********* ** ** ** ** ** ** ** */
/* ********* ** ** ** ** ** ** ** */
/* ** ** ** ** ** ** ** ** */
/* ** ** ** ** ** ** ** ** ** */
/* ** ** ** ** ** ** ** ** ** */
/* ********* ** **** ** ** ********* ** */
/* ********* ** *** ***** ********* ** */
/* */
/****************************************************************//********************************************************************************************************/
/* Programme Realiser par mr Saifeddine Maatoug */
/* le 10/03/2004 */
/* Il s’agit d’un proget d’algorithmique dans l’ecole E.S.T.I */
/********************************************************************************************************/#include “stdio.h”
#include “conio.h”
#define n 100
#define nb_max 12
typedef struct
{
char name[20];
char prenom[20];
int niveau;
char sexe[1];
int nb_m;
int cin;
int age;
}etudianttype;
typedef struct
{
char matiere[20];
float note;
int coef;
}tmatiere;
typedef struct
{
tmatiere t[nb_max];
}ttmatiere;
/************************************************************************************************************/
/************************************************************************************************************/
/*******************************/
/* fonction moyenne eleve i */
/*******************************/
float moyenne(int m);
{
float r,sc,sm;for(i=0;i<etudiant[m].nb_m;i++)
{
sm=((tttmatiere[m].t.note)*(tttmatiere[m].t.coef)) +sm;
sc=tttmatiere[m].t.coef+sc;
}return(sm/sc);
}
/* fin fonction moyenne *//***********************************************************************************************************/
/*******************************/
/* fonction classement eleve i */
/*******************************/int classement(int c);
{
int r=all;
for(i=0;i<all;i++)
{
if (moyenne(i)>moyenne(c))
{
r–;
}
return(r);}
/* fin fonction classement *//***********************************************************************************************************/
/***********************************/
/* procedure clear screen */
/***********************************/void clrscr()
{
int i,n=15;for(i=0;i<n;i++)
{
printf(“\n”);
printf(“\n”);}
} /* fin procedure clear screen *//***********************************************************************************************************/
/*************************************************************************************/
/*procedure annulation des chaines de caracters [(.) ==> est pris comme valeur nulle]*/
/*************************************************************************************/void vidage(int k)
{
void main();
int c,u;etudiant[k].cin=0;
etudiant[k].niveau=0;
etudiant[k].sexe[1]=’.’;
etudiant[k].nb_m=0;for(c=0;c<20;c++)
{
etudiant[k].name[c]=’.’;
etudiant[k].prenom[c]=’.’;
}
for(u=0;u<nb_max;u++)
{
tttmatiere[k].t.matiere=’.’;
tttmatiere[k].t.note=0;
tttmatiere[k].t.coef=0;
}}
/* fin procedure annulation *//************************************************************************************************************/
/************************************************/
/* procedure affichage d’un etudiant par besoin */
/************************************************/void affichage(int i,int all)
{
void main();
int j,c,k=0;
/*affiche nom*/clrscr();
printf(“\nNom: “);
for(c=0;c<20;c++)
{
if (etudiant.name[c]==’.’){break;} // eof pour nom
printf(“%c”,(etudiant.name[c]));
}
/*affiche prénom*/
printf(“\nPrenom: “);
for(c=0;c<20;c++)
{
if (etudiant.prenom[c]==’.’){break;} // eof pour prénom
printf(“%c”,(etudiant.prenom[c]));
}
/* affiche sexe*/
printf(“\nSexe: %c”,etudiant.sexe[1]);//fin sexe
/*affiche Numero carte identite */
printf(“\nNumeor carte identite: %i\n”,etudiant.cin);// fin C.I.N
/*affiche age*/
printf(“age :%i”,etudiant.age);
/* boucle matieres */
printf(“cette etudiant etuide %i matieres “,etudiant.nb_m); //combient de matiere etudie cette etudiant
for(c=0;c<nb_m;c++)
if (k!=0)/*matiere afficheé donc on affiche note */{printf(“: %0.3f\n”,tttmatiere.note); // note de la matiere c apres affichage matiere
{
for(j=0;j<20;j++)
{
k++; // valeur pour savoire es la matiere est afficheé
if(tttmatiere.t[c].matiere[j]==’.’){break;} // eof pour nom matiere
printf(“%c”,tttmatiere.t[c].matiere[j]);
}}
printf(“\nMoyenne :%0.3f”,moyenne(i));
printf(“\nClassement : %i”,classement(i));
printf(“pour revenir au menu principal appuiez (y)”);if(getch()==’y’|’Y’){main();} // condition pour revenir au menu princiapl}
/* fin procedure affichage*//************************************************************************************************************/
/************************************************/
/* Procedure saisie d’un nouveau etudiant */
/************************************************/void saisie(int i,int all)
{
void main();
vidage(i);
int c;
/* saisie nom */
printf(“\nDonnez Nom –S.V.P– –il faux ecrire 15 caracteres \npour les caracteres de plus vous pouvez les replacez par des points\n\01”);
scanf(“%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c”,&etudiant.name[0],&etudiant.name[1],&etudiant.name[2],&etudiant.name[3],&etudiant.name[4],&etudiant.name[5],&etudiant.name[6],&etudiant.name[7],&etudiant.name[8],&etudiant.name[9],&etudiant.name[10],&etudiant.name[11],&etudiant.name[12],&etudiant.name[13],&etudiant.name[14]); // saisie nom
/* fin saisie nom */
printf(“\nDonnez Prenom –S.V.P– –il faux ecrire 15 caracteres \npour les caracteres de plus vous pouvez les replacez par des points\n\01”);
scanf(“%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c”,&etudiant.prenom[0],&etudiant.prenom[1],&etudiant.prenom[2],&etudiant.prenom[3],&etudiant.prenom[4],&etudiant.prenom[5],&etudiant.prenom[6],&etudiant.prenom[7],&etudiant.prenom[8],&etudiant.prenom[9],&etudiant.prenom[10],&etudiant.prenom[11],&etudiant.prenom[12],&etudiant.prenom[13],&etudiant.prenom[14]);// saisie prenom
/* fin saisie prenom */
printf(“\nDonnez N:C.I.N –S.V.P–\n\01”);
scanf(“%i”,&etudiant.cin); // saisie numero carte identite
while(etudiant.sexe[1]!=’M’|’F’) // controle sexe etudiant(e)
{
printf(“\nDonnez sexe (M/F)\n\01”); //saisie sexe etudiant(e)
scanf(“%c”,&etudiant.sexe[1]);
}
printf(“\nDonnez nombre de matiere etudieé par cette eleve\n\01”); //saisie nombre de matiere par etudiant
scanf(“%i”,&etudiant.nb_m);
for(c=0;c<etudiant.nb_m;c++)
{
printf(“\nDonnez Nom matiere: %i –S.V.P– –il faux ecrire 15 caracteres \npour les caracteres de plus vous pouvez les replacez par des points\n\01”,c);
scanf(“%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c”,&tttmatiere.t[c].matiere[0],&tttmatiere.t[c].matiere[1],&tttmatiere.t[c].matiere[2],&tttmatiere.t[c].matiere[3],&tttmatiere.t[c].matiere[4],&tttmatiere.t[c].matiere[5],&tttmatiere.t[c].matiere[6],&tttmatiere.t[c].matiere[7],&tttmatiere.t[c].matiere[8],&tttmatiere.t[c].matiere[9],&tttmatiere.t[c].matiere[10],&tttmatiere.t[c].matiere[11],&tttmatiere.t[c].matiere[12],&tttmatiere.t[c].matiere[13],&tttmatiere.t[c].matiere[14]); // saisie Nom matierewhile(tttmatiere.t[c].note<0)
{printf(“\nDonnez ca note\n\01”);scanf(“%f”,&tttmatiere.t[c].note);} // saisie note matiere de l’etudiant (i) matiere (c)
while(tttmatiere.t[c].coef<0)
{printf(“\nDonnez son coeficient\n\01”);scanf(“%i”,&tttmatiere.t[c].coef);} // saisie coef matiere (c) de l’etudiant (i)}
while(etudiant.age<=0)
{
printf(“\ndonnez age etudiant\n”);
scanf(“%i”,&etudiant.age);
}while((c>2)||(c<=0))
{
printf(“\n\tDonnez votre choix \n”);
printf(“1-nouveau eleve\n”);
printf(“2-revenir au menu principal\n”)
printf(“\01”);
scanf(“%i”,&c);
}
clrscr();
if(c==1){saisie(all);}
if(c==2){main();}
}/* fin procedure saisie */
/***********************************************************************************************************/
/**************************************/
/* procedure Recherche */
/**************************************/
void recherche(int all){
void main();char ch_nom[15],ch_prenom[15];
int c,chi,ch_cin;clrscr(); // effacer l’ecran
printf(“\nDonnez votre choix S.V.P \n”);
printf(“1-Nom\n”);
printf(“2-Prenom\n”);
print(“3-C.I.N\n”);scanf(“%i”,&chi); //saisie de choix 1 . 2 . 3
switch(chi) // selon choix faire
{
case 1: { //debut choix 1printf(“\nDonnez Nom a RECHERCHER –S.V.P– –il faux ecrire 15 caracteres \npour les caracteres de plus vous pouvez les replacez par des points\n\01”);
scanf(“%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c”,&ch_name[0],&ch_name[1],&ch_name[2],&ch_name[3],&ch_name[4],&ch_name[5],&ch_name[6],&ch_name[7],&ch_name[8],&ch_name[9],&ch_name[10],&ch_name[11],&ch_name[12],&ch_name[13],&ch_name[14]); // saisie nom a rechercher
for(chi=0;chi<all;chi++)
{
trc=0;
for(c=0;c<15;c++) //boucle recherche nom
{
if (etudiant[chi].name[c]==ch_name[c]){trc++;} // boucle recherche caractere par caractere
}
if (trc==15){trc=chi;break;}
else{trc=0;}
break; // pour le case 1
}
} //fin choix 1case 2: { //debut choix 2
printf(“\nDonnez Prenom a RECHERCHER –S.V.P– –il faux ecrire 15 caracteres \npour les caracteres de plus vous pouvez les replacez par des points\n\01”);
scanf(“%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c”,&ch_prenom[0],&ch_prenom[1],&ch_prenom[2],&ch_prenom[3],&ch_prenom[4],&ch_prenom[5],&ch_prenom[6],&ch_prenom[7],&ch_prenom[8],&ch_prenom[9],&ch_prenom[10],&ch_prenom[11],&ch_prenom[12],&ch_prenom[13],&ch_prenom[14]); // saisie prenom a rechercher
for(chi=0;chi<all;chi++)
{ trc=0;
for(c=0;c<15;c++) // boucle recherche prenom
{
if (etudiant[chi].prenom[c]==ch_prenom[c]){trc++;} //recherche caractere par caratere
}
if (trc==15){trc=chi;break;}
else{trc=0;}
break; // pour le case 2
}
} //fin choix 2case 3: { // choix 3
printf(“\nDonnez Numero C.I.N a RECHERCHER \n”);
scanf(“%i”,&ch_cin); //saisie cin a rechercher
for(chi=0;chi<all;c++)
{
if(etudiant[c].cin==ch_cin){trc=c;break;}
else {trc=0;}
}
break;// pour le case 3
} // fin choix 3
default:{printf(“le choix n’est pas valide”);getch();recherche(all);}break;
}
if (trc!=0)
{ //condition pour un etudiant existant
printf(“\n—-Etudiant existant—\n “);
printf(“Entrez votre choix\n”);
printf(“1-Continuer ou Retour au menu\n”);
printf(“2-afficher Fiche Etudiant”);
printf(“3-Rechercher un autre Etudiant\n”);
scanf(“%i”,&c);
clrscr(); // effacer l’ecran
switch (c)
{case 1:break;
case 2: affichage(trc,all);break;
case 3:recherche(all);break;}
}
else {
printf(“\nje ne peux rien confirmer car \nl’eleve ne se trouve pas aparament dans la liste\n”);
printf(“Entrez votre choix\n”);
printf(“1-Retour au menu\n”);
printf(“2-Rechercher un autre Etudiant\n”);
scanf(“%i”,&c);
switch(c)
{
case 1:main();break;
case 2:recherche(all);break;}
}
}/* fin procedure recherche */
/************************************************************************************************************/
/**************************/
/* procedure modification */
/**************************/void modif(int md)
{void main();
int c;
clrscr();
printf(“\nEntrez votre choix\n”);
printf(“1-modifier Nom\n”);
printf(“2-modifier prenom\n”);
printf(“3-modifier C.I.N\n”);
printf(“4-modifier sexe\n”);
printf(“5-modifier niveau\n”);
printf(“6-modifier age\n”);
scanf(“%i”,&c);
switch(c)
{case 1:{ // modifier nom
printf(“\nDonnez le nouveau Nom –S.V.P– –il faux ecrire 15 caracteres \npour les caracteres de plus vous pouvez les replacez par des points\n\01”);
scanf(“%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c”,&etudiant[md].name[0],&etudiant[md].name[1],&etudiant[md].name[2],&etudiant[md].name[3],&etudiant[md].name[4],&etudiant[md].name[5],&etudiant[md].name[6],&etudiant[md].name[7],&etudiant[md].name[8],&etudiant[md].name[9],&etudiant[md].name[10],&etudiant[md].name[11],&etudiant[md].name[12],&etudiant[md].name[13],&etudiant[md].name[14]); // saisie nom a rechercher}break;
case 2:{ // modifier prenom
printf(“\nDonnez le nouveau Prenom –S.V.P– –il faux ecrire 15 caracteres \npour les caracteres de plus vous pouvez les replacez par des points\n\01”);
scanf(“%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c”,&etudmdant[md].prenom[0],&etudmdant[md].prenom[1],&etudmdant[md].prenom[2],&etudmdant[md].prenom[3],&etudmdant[md].prenom[4],&etudmdant[md].prenom[5],&etudmdant[md].prenom[6],&etudmdant[md].prenom[7],&etudmdant[md].prenom[8],&etudmdant[md].prenom[9],&etudmdant[md].prenom[10],&etudmdant[md].prenom[11],&etudmdant[md].prenom[12],&etudmdant[md].prenom[13],&etudmdant[md].prenom[14]);// samdsmde prenom}break;
case 3:{ //modifier C.I.N
printf(“\nDonnez nouveau numero C.I.N\n”);
scanf(“%i”,&etudiant[md].cin);
}break;case 4:{ //modifier sexe
printf(“\nDonner nouveau sexe !!!!\n”);
scanf(“%c”,&etudiant[md].sexe[1]);}break;
case 5:{ //modifier niveau
while(etudiant[md].niveau<=0)
{
printf(“\nDonnez nouvea niveau\n”);
scanf(“%i”,&etudiant[md].niveau);
}
}break;case 6:{ //modifier age
while(etdiant[md].age)
{
printf(“\nDonnez nouveau age\n”);
scanf(“%i”,&etudiant[md].age);
}}break;
default: {printf(“Modification n’est pas reussite”);c=0;break;} //message de modification nulle
}
if(c!=0)printf(“\nModificatin reussite …..\n”); //modification positive
printf(“\nDonnez votre choix –S.V.P–“);
printf(“\n1-refaire une autre modification”);
printf(“\n2-revenir au menu”);
scanf(“%i”,&c);
switch(c)
{
case 1:modif(md);break;
case 2:main();break;
}
}
/* fin procedure modification *//************************************************************************************************************/
/************************************************************************************************************/
/*********************************************** Bienvenue **************************************************/
/******************** Procedure principal de programme gestion de scolarite *********************************/
/************************************************************************************************************/
/************************************************************************************************************/void main()
{
etudianttype etudiant[n];
ttmatiere tttmatiere[n];
int all=0,one=7;
int trc=all;
// debut bienvenue
while (one!=0)
{
printf(“\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1”);printf(“——————————————————————————–“);
printf(“———— Bienvenue sur le menu de gestion scolarite E.S.T.I —————-“);
printf(“——————————————————————————–“);
printf(“\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1\1”);// fin bienvenue
printf(“\nEntrez votre choix\n”);
printf(“\1-1-Saisie d’un nouveau etudiant\n”);
printf(“\1-2-Recherche d’un etudiant\n”);
printf(“\1-3-Modification de parametres d’un etudiant\n”);
printf(“\1-4-Afficher la fiche d’un etudiant\n”);
printf(“\1-5-Quitter\n”);
scanf(“%i”,&one);switch(one)
{
case 1:{
clrscr();
vidage(all); // vidage de la partie a saisir pour avoir une saiie reussite et parfaite
saisie(all);all++ // incrementation de nb total d’etudiant en supposant qu’il y a un nouveau elmen saisie}break;
case 2:{
clrscr();
recherche(); // recherche par parametres}break;
case 3:{
clrscr();
printf(“——————————————————————————–“);
printf(“———-pour Modifier un element il faux le rechercher en premier lieu——–“)
printf(“——————————————————————————–\n”);
recherche();
modif(trc);}break;
case 4:{clrscr();
printf(“——————————————————————————–“);
printf(“———-pour AFFICHER un element il faux le rechercher en premier lieu——–“)
printf(“——————————————————————————–\n”);
recherche();
affichage(trc);}break;
case 5:{;}break;default:{printf(“votre choix n’est pas valide “);getch();main();}break;
}
}
printf(“——————————————————————————–“);
printf(“————————Merci d’avoir choisi notre programme——————–“);
printf(“——————————————————————————–\n”);}
my compiler is on ……
errors are
Code:——————–Configuration: bjh – Win32 Debug——————–
Compiling…
jnk.cpp
c:\bjh\jnk.cpp(89) : error C2447: missing function header (old-style formal list?)
c:\bjh\jnk.cpp(112) : error C2447: missing function header (old-style formal list?)
c:\bjh\jnk.cpp(559) : fatal error C1004: unexpected end of file found
Error executing cl.exe.jnk.obj – 3 error(s), 0 warning(s)
Last edited by enjoy; 05-02-2004 at 02:22 PM. Reason: adding errors
05-02-2004 #2
XSquared XSquared is offline
C++ Developer
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Jun 2002
Location
Ontario, Canada
Posts
2,718
1: #include “stdio.h”
#include <stdio.h>2: void main()
int main()What errors are you getting?
Naturally I didn’t feel inspired enough to read all the links for you, since I already slaved away for long hours under a blistering sun pressing the search button after typing four whole words! – QuzahYou. Fetch me my copy of the Wall Street Journal. You two, fight to the death – Stewie
05-02-2004 #3
enjoy enjoy is offline
/*enjoy*/
Join Date
Apr 2004
Posts
159
i’m using visual c++
“stdio.h” equivalent <stdio.h>
int main() == void main() == void main(void)
05-02-2004 #4
XSquared XSquared is offline
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Location
Ontario, Canada
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>”stdio.h” equivalent <stdio.h>
Nope.>int main() == void main() == void main(void)
int main() != void main() != void main(void)
Search the fscking board.
Naturally I didn’t feel inspired enough to read all the links for you, since I already slaved away for long hours under a blistering sun pressing the search button after typing four whole words! – QuzahYou. Fetch me my copy of the Wall Street Journal. You two, fight to the death – Stewie
05-02-2004 #5
enjoy enjoy is offline
/*enjoy*/
Join Date
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159
try to compile this program and see the errors
please …..
05-02-2004 #6
enjoy enjoy is offline
/*enjoy*/
Join Date
Apr 2004
Posts
159
Code:
?
1
try to compile my code because my compiler is busy … :d
05-02-2004 #7
anonytmouse anonytmouse is offline
Yes, my avatar is stolen
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Posts
2,544
Here is the biggest problem:
Code:
float moyenne(int m);
{
float r,sc,sm;
That semicolon should not be there.
Also:
Code:
?
1
2
3
int classement(int c);
{
int r=all;
Once you have fixed those, you need to fix these:
Code:
?
1
2
3
4
5
6
7
8
9
10
testbed3.c(67) : error C2065: ‘i’ : undeclared identifier
testbed3.c(67) : error C2065: ‘etudiant’ : undeclared identifier
testbed3.c(67) : error C2109: subscript requires array or pointer type
testbed3.c(69) : error C2065: ‘tttmatiere’ : undeclared identifier
testbed3.c(69) : error C2109: subscript requires array or pointer type
testbed3.c(69) : error C2109: subscript requires array or pointer type
testbed3.c(70) : error C2109: subscript requires array or pointer type
testbed3.c(88) : error C2065: ‘all’ : undeclared identifier
…
testbed3.c(294) : fatal error C1003: error count exceeds 100; stopping compilation
05-02-2004 #8
enjoy enjoy is offline
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Join Date
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Posts
159
Code:
testbed3.c(67) : error C2065: ‘i’ : undeclared identifier
[ b] i is declared in any function who is used ???[/b]
testbed3.c(67) : error C2065: ‘etudiant’ : undeclared identifier
etudiant is declared in the main function
testbed3.c(67) : error C2109: subscript requires array or pointer type
?????
testbed3.c(69) : error C2065: ‘tttmatiere’ : undeclared identifier
tttmatiere is declared in the main
testbed3.c(69) : error C2109: subscript requires array or pointer type
testbed3.c(69) : error C2109: subscript requires array or pointer type
testbed3.c(70) : error C2109: subscript requires array or pointer type
????????????!!!!!!
testbed3.c(88) : error C2065: ‘all’ : undeclared identifier
all is deeclared in the main
…
Code:
?
1
explain me please these errors
05-02-2004 #9
anonytmouse anonytmouse is offline
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‘Undeclared Identifier’ simply means that you have not declared that variable in that scope.>> etudiant is declared in the main function <<
That means it is available in the main() function. It is not available in other functions unless you pass it to them or declare it at file scope.
05-02-2004 #10
enjoy enjoy is offline
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what’s the file scope
excuse me my english is not good i’m just a beginner in english
05-02-2004 #11
anonytmouse anonytmouse is offline
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Code:
/* Declared outside a function. Has global scope. Visible in all
* functions in the project. */
int a;/* Declared outside a function with static specifier. Has file scope.
* Visible in all functions in this file only. */
static int b;int main(void)
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